Nuclear rotational band ($E_I-E_0={\hslash }^{2}I(I+1)/(2\mathcal{J})$)

A sequence of nuclear energy levels interpreted as different total angular momenta built on approximately the same intrinsic structure. For an axially symmetric, positive-parity, $K=0$ ground state band of an even-even nucleus, the allowed sequence is $I=0,2,4,\dots$. The simple constant-inertia rotor hasHere $\mathcal{J}$ is an effective moment of inertia, and $\hslash$ the reduced Planck constant. The even-$I$ restriction belongs to this particular intrinsic symmetry and band, rather than to all nuclear excitations. The angular momentum operator eigenvalue supplies $I(I+1)$, rather than the classical replacement $I^2$.

Set $ϵ=E_2-E_0$. Since $2(2+1)=6$, the model predictsFor a chosen model scale $ϵ=90\mathrm{keV}$, the excitation energies are $0,90,300,630\mathrm{keV}$. The corresponding successive gamma ray energies are approximately $90,210,330\mathrm{keV}$, neglecting nuclear recoil. Level energies and emitted line energies are different lists. These numbers illustrate the formula and are not a measured isotope spectrum.

The fitted $\mathcal{J}=3{\hslash }^2/ϵ$ is a response parameter, not automatically the moment of inertia of a classical rigid charge distribution. Nuclear pairing changes this response; Ben Roy Mottelson connected observed inertias with correlations beyond independent-particle motion.^[ref]

At larger angular momentum, changing intrinsic structure or nuclear pairing can invalidate a single constant $\mathcal{J}$. A useful diagnostic is to compare $(E_I-E_0)/[I(I+1)]$ across several levels: constancy tests the simple formula, while a drift identifies the need for additional physics. A successful ratio alone neither specifies every microscopic motion nor measures a literal solid-body rotation.

Aage Niels Bohr's 1975 lecture presents a plutonium ${}^{238}\mathrm{Pu}$ spectrum deduced from the fine structure of alpha decay of curium ${}^{242}\mathrm{Cm}$. The readout was decay-line energy; the comparison fixed the rotor scale from the first excitation and tested the remaining levels against $I(I+1)$. The lecture reports spectroscopy, rather than a laboratory setup operated by its author.^[ref]

His measured erbium ${}^{166}\mathrm{Er}$ $K=0$ band has excitation energies $0$, $80.56$, $265.0$, $545.4$ and $911.2\mathrm{keV}$ for $I=0,2,4,6,8$. The same lecture analyzes interband electric quadrupole transitions, adding tests beyond level positions.^[ref]

Using those first two excitations gives $265.0/80.56\simeq 3.28947$, close to the ideal $10/3$, and distinct from the ideal harmonic value $2$. Fixing the rotor scale with $80.56\mathrm{keV}$ predicts $268.53\mathrm{keV}$ at $I=4$ and $563.92\mathrm{keV}$ at $I=6$. The measured values lie about $1.32\%$ and $3.28\%$ below these predictions. This is a useful limit of the simple model: the pattern supports a rotational interpretation while revealing departures from constant inertia. It does not by itself determine a unique nuclear charge distribution. Reconstructing a level scheme also requires assigning which transitions connect which states; raw peak positions alone do not provide all spins, parities or transition strengths.