Past exam of the biological physics course of the University of Oxford / 2017 / 4 / d

At fixed voltage let $a$ and $b$ be opening and closing rates. The open probability obeysThis illustrates equal open probability with unequal ion-channel relaxation times: both channels have $p_{\infty }=1/2$, but channel A has ${\tau }_A=1\mathrm{ms}$ and channel B has ${\tau }_B=0.1\mathrm{ms}$. Starting closed, $p_A(t)=\frac{1}{2}(1-e^{-t/(1\mathrm{ms})})$ and $p_B(t)=\frac{1}{2}(1-e^{-t/(0.1\mathrm{ms})})$. If channel number, unitary conductance and driving force agree, both have the same steady macroscopic current; B approaches it ten times faster.

An individual channel remains either open or closed. Its mean closed and open dwell times are $1/a$ and $1/b$, respectively: both are $2\mathrm{ms}$ in A and $0.2\mathrm{ms}$ in B. Thus identical equilibrium open probability does not imply identical kinetics or noise correlation time. Ensemble probability relaxation depends on the sum of rates, while the mean dwell in a given state depends on its exit rate.