Choose distinct points of . The vectors lie in the -dimensional vector space , so they are linearly dependent. Hence there are real numbers , not all zero, such thatThe second equality forces both a positive and a negative coefficient. Put , , andRearranging the first equality givesEach side is a convex combination: the coefficients are positive and sum to one. Thus belongs to both convex hulls. Place the points with indices in in , those with indices in in , and assign every zero-coefficient point and every remaining point of to . Then are nonempty, disjoint, and have union . Adding points cannot shrink a convex hull, soThis proves the intersecting convex hull partition theorem, including when has more than points or is infinite: only the initial finite collection was needed.
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