Since the steady state is strictly positive, the positive-part function is differentiable in a neighbourhood of it. Write . Retaining first-order terms givesSubstitute the exponential mode to obtainHere the last equality uses the exact steady-state equation. For small , and . Linearizing at the exact root avoids carrying a spurious constant residual from the printed approximate equilibrium.
Articles by others on the same topic
There are currently no matching articles.