Past exam of the mathematics course of the University of Cambridge / 2013 / iii / Paper 47 / 1

Use the Minkowski metric with signature $(+,-)$, so the Sine-Gordon equation is ${\varphi }_{tt}-{\varphi }_{xx}+\sin \varphi =0$. The light-cone coordinates here satisfyIn particular, there is no extra factor of four with this coordinate normalization. The Bäcklund transformation requires $a\ne 0$, because one of its equations contains $a^{-1}$.

Put $F=(\psi +\varphi )/2$ and $G=(\psi -\varphi )/2$. In the parameter convention of this paper the Sine-Gordon Bäcklund transformation gives $G_{+}=a\sin F$ and $F_{-}=a^{-1}\sin G$. Differentiating, for a twice differentiable transformed field, givesSince $\psi =F+G$, the addition formula yields ${\psi }_{+-}=\sin (F+G)=\sin \psi$. Therefore the transformed field satisfies the same Sine-Gordon equation:Subtracting the two differentiated equations also gives ${\varphi }_{+-}=\sin \varphi$, showing the compatibility with the seed equation. This proves the unheaded request before the numbered parts, without assuming a particular soliton form.

With zero seed, both Bäcklund transformation equations concern ${\varphi }_a/2$. On a nonconstant branch, separation of variables uses $d\log |\tan ({\varphi }_a/4)|=d{\varphi }_a/[2\sin ({\varphi }_a/2)]$, givingFor $C>0$, absorb its magnitude into an additive constant $c=\log C$ in the exponent. A convenient smooth representative isThe constant-phase condition for this traveling profile determines its velocity:The profile is a traveling soliton with velocity $v_a=(1-a^2)/(1+a^2)$, strictly between $-1$ and $1$. The scalar-field vacua on the two sides differ by $2\pi$. With the topological charge convention $Q=[\varphi (+\infty )-\varphi (-\infty )]/(2\pi )$, this branch has $Q=\mathrm{sgn}a$: it is a Sine-Gordon kink for $a>0$ and an antikink for $a<0$. Its width is proportional to ${\gamma }_a^{-1}$, and its derivative decays exponentially away from its center, giving a finite-energy field configuration.

For completeness, the classical rest mass in this paper's coupling convention is $8m/\beta$, as derived in Question 2; a Lorentz boost gives energy $8m{\gamma }_a/\beta$. This localized, topologically protected traveling field is the required classical field-theory soliton. A negative $C$ reverses the field and hence the topological charge; $C=0$ gives the vacuum rather than a soliton. Vacuum shifts by $4\pi$ can be made without changing the displayed Bäcklund transformation equations.

Choose the positive-exponential branches from part (i) and set their additive constants to zero. First take $0<b<1$, and defineThen $\tan ({\varphi }_b/4)=e^{\gamma (x-vt)}$ and $\tan ({\varphi }_a/4)=e^{-\gamma (x+vt)}$. The tangent subtraction formula givesConsequently the allowed Sine-Gordon superposition formula produces the smooth fieldThis is the negative of the Sine-Gordon two-kink solution, and hence a two-antikink configuration. The auxiliary seeds have opposite topological charges, but their charges cannot simply be added to infer the charge of the nonlinear two-step Bäcklund transformation. Indeed, the displayed final field tends to $2\pi$ at the left spatial end and $-2\pi$ at the right, so its total topological charge is $-2$.

Let $T=|t|$ become large. Near the right transition, $x=vT+O(1)$, the tangent argument has the asymptotic formso the local field is $-4\arctan e^{\gamma (x-vT)+\log v}$, a single antikink. Near the left transition, the local field is $4\arctan e^{-\gamma (x+vT)+\log v}+o(1)$, again a decreasing antikink. The resulting asymptotic center lines areThus two incoming antikinks with topological charges $(-1,-1)$ and velocities $(+v,-v)$ separate again with exactly the same topological charges and velocities. There is no radiative tail in these asymptotic profiles. Labeling the outgoing objects by their preserved rapidities makes this elastic soliton scattering; labeling the left and right lumps instead describes reflection with exchanged velocities.

For the right-moving soliton, its incoming intercept is ${\gamma }^{-1}\log v$ and its outgoing intercept is $-{\gamma }^{-1}\log v$. The spatial shifts are therefore $\Delta x_{+}=-2{\gamma }^{-1}\log v$ and $\Delta x_{-}=2{\gamma }^{-1}\log v$. Define the soliton time delay as the change in arrival time at a fixed distant spatial point relative to continuation of the incoming straight line, so $\Delta t=-\Delta x/v_{\mathrm{particle}}$. Both objects have the same signed soliton time delay, which is an advance:This is the Sine-Gordon two-kink time advance. In physical coordinates $T_{\mathrm{phys}}=t/m$, the time shift is $2\log v/(m\gamma v)$. The explicit intercepts fix the sign convention unambiguously.

The remaining real parameter choices are covered without changing the calculation. For any $b\ne 0$ with $b^2\ne 1$, put $v_b=(1-b^2)/(1+b^2)$, $u=|v_b|$, $\gamma =(|b|+|b{|}^{-1})/2$ and $ϵ=\mathrm{sgn}(b{v}_b)$. The same choice of zero additive constants givesEach scattered object's topological charge is $-ϵ$, the velocities are $\pm u$, and the signed soliton time delay is $2\log u/(\gamma u)$. If $b=\pm 1$, the superposition coefficient vanishes and this representative is the vacuum; there is no pair of separated moving solitons and no scattering delay to assign. Thus the scattering conclusion requires the nondegenerate case $0<u<1$.