The proposed noncyclic interchange is false. With matrix units,one hasTrace is invariant under cyclic permutations, but an arbitrary swap need not be cyclic.
The characteristic polynomial of isA scalar is an eigenvalue when there is a nonzero vector such thatSuch a is an eigenvector belonging to . Equivalently, is a root of and the corresponding eigenvectors are the nonzero elements of .
Consider the real polynomialThe hypothesis says , so is not identically zero. A nonzero polynomial has only finitely many roots, whereas is infinite. Hence there is a real withThus is invertible, as summarized by the real parameter avoiding a singular matrix pencil.
Write the complex similarity matrix aswith real. From we obtain , and equating real and imaginary parts givesThereforefor every real .
Now is a real polynomial andThus some real has . Taking , we have a real invertible matrix satisfying , orThis proves real similarity from complex similarity.
Eigenvectors belonging to distinct eigenvalues are linearly independent. Indeed, supposeis a shortest nontrivial relation, where and the are distinct. Applying givesa shorter nontrivial relation, a contradiction.
Thus distinct eigenvalues provide a basis of eigenvectors, proving that is diagonalizable over . If is real and all its eigenvalues are real, each real singular matrix has a nonzero real null vector. Choosing one for each eigenvalue gives a real eigenbasis. Hence the real matrix is diagonalizable over . This is the distinct eigenvalues imply diagonalizability criterion.
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