Past exam of the MPhil in micro- and nanotechnology enterprise course of the University of Cambridge / 2023 / Paper 1 / Section A(ii) / 3

For a positive photoresist, let $D_r$ be the largest dose retaining the nominal film and $D_c$ the clearing dose. With the conventional photoresist contrast definition,For a sinusoidal aerial image, the bright-to-dark dose ratio is $(1+C)/(1-C)$, where $C$ is the Michelson contrast. A dose window that clears bright regions while retaining dark regions requiresThis assumes a fully modulated input pattern and that the plotted modulation transfer function gives the aerial-image contrast. It is a dose-window criterion, not a statement that the resist creates optical information absent from the image.^[ref]

The two thresholds are approximatelyReading their intersections with the supplied curve gives, to graphical accuracy,for the lower- and higher-contrast resists respectively. These are the results independent of the dimensional frequency convention. Their minimum full periods are $P=1/\nu$, and equal line/space widths are half those periods:An ArF excimer laser uses $\lambda \simeq 193\mathrm{nm}$. A numerical length requires specifying what the caption's “Rayleigh limit” means. Taking it literally as the reciprocal of the Rayleigh criterion point separation givesIf instead the graph uses the common incoherent-cutoff normalization ${\nu }_0=2\mathrm{NA}/\lambda$, the widths are $302\mathrm{nm}$ and $201\mathrm{nm}$, with periods twice those values. The caption does not explicitly provide an equation for ${\nu }_0$ or define whether “feature size” means period or half-pitch, so these conventions must not be silently mixed. The higher-contrast resist resolves the higher normalized frequency in either convention.

An on-axis point illuminator increases spatial coherence. It is not a point object, and it does not remove diffraction. For an ideal aberration-free pupil, coherent imaging is linear in field amplitude and has cutoffFor a real amplitude grating $U(x)=a[1+m\cos (2\pi \nu x)]$, with $0\le m\le 1$ and all three field orders inside this pupil, the intensity contrast is $C=2m/(1+m^2)$. Flat coherent field transfer preserves this contrast; weak input modulation does not itself meet a high resist contrast threshold. Assume a sufficiently high-contrast amplitude mask: for example, $m=1$ gives $C=1$, exceeding both resist thresholds. Under this assumption, both resists have the same limiting equal-line/space widthThis is an approach to the cutoff from below; finite dose latitude, aberrations and a real binary mask can make usable resolution worse. A general coherent intensity image cannot be obtained by applying an incoherent intensity MTF unchanged: $I=|h\ast U{|}^2$, rather than $I=|h{|}^2\ast |U{|}^2$.^[ref]

With ${\nu }_0=2\mathrm{NA}/\lambda$, this coherent cutoff is $0.5{\nu }_0$: the low-contrast resist improves from roughly $302$ to $241\mathrm{nm}$, while the high-contrast resist worsens from roughly $201$ to $241\mathrm{nm}$. Coherence improves contrast within its passband but reduces the ultimate bandwidth relative to incoherent illumination.

With the literal Rayleigh-spacing normalization ${\nu }_0=1/R_R$, the same physical cutoff is instead $0.61{\nu }_0$, not $0.5{\nu }_0$. The corresponding widths from the preceding part would improve from roughly $368$ and $245\mathrm{nm}$ toward $241\mathrm{nm}$. The cutoff in physical units is unambiguous under the stated ideal on-axis model; the claimed direction and size of a change inferred from the plotted normalized axis depend on its definition. Off-axis illumination, partial coherence and arbitrary phase objects require a fuller imaging model.

Depth of focus is the axial tolerance over which the projected pattern remains acceptable. Wafer topography, resist thickness, wafer tilt and focus-setting errors can move part of the film outside that range, reducing contrast and changing printed linewidth. Increasing numerical aperture can improve lateral resolution while reducing this axial process window.

Using the supplied coefficient in the conventional expression,This is the range assigned to DOF by that convention. Whether an instrument reports a full allowable interval or a one-sided defocus tolerance must be stated separately; an additional factor of two cannot be inferred from the numerical coefficient alone.