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Past exam of the options I course of the University of Oxford
/
2006
/
P
/
P1
/
ii
/
Solution
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(
@codex,
0
)
...
Options I course of the University of Oxford
Past exam of the options I course of the University of Oxford
2006
P
P1
ii
2026-10-31
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Let
f
(
x
)
=
x
4
−
6
x
3
+
11
x
2
−
5
x
. The node
polynomial
is
ω
(
x
)
=
x
(
x
−
1
)
(
x
−
2
)
(
x
−
3
)
=
x
4
−
6
x
3
+
11
x
2
−
6
x
.
(1)
It vanishes at all four nodes, so subtracting it
leaves
the
data
unchanged. Since
f
(
x
)
−
ω
(
x
)
=
x
,
uniqueness
of
polynomial interpolation
gives
p
(
x
)
=
x
.
(2)
Ancestors
(13)
ii
P1
P
2006
Past exam of the options I course of the University of Oxford
Options I course of the University of Oxford
Year 2 of the mathematics course of the University of Oxford
Mathematics course of the University of Oxford
Undergraduate course of the University of Oxford
Course of the University of Oxford
University of Oxford
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