Write and for the axial source and observation distances, and put . The aperture is . Under the Fresnel diffraction, the spherical incident wave amplitude is effectively constant over this small aperture, while its quadratic wave phase must be retained. Therefore the two transverse integrals separate:
where contains the source strength, the propagation distances and a common phase factor.
Use the dimensionless variable and define the optical normalization of Fresnel integrals
The oddness of makes the bracket , so
This square-aperture Fresnel diffraction normalization is especially useful for comparing with no aperture. In the same Fresnel diffraction, the unrestricted one-dimensional Fresnel integral is ; its square is . Thus, writing for the unobscured field at the same point,
The normalization has the correct no-aperture limit because in this convention.

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