Past exam of the physics course of the year 1 of the natural sciences course of the University of Cambridge / 2024 / Paper 1 / Section B / 6 / c / Solution

Let $m_p=0.250\mathrm{kg}$ and let $m_w$ be the hanging mass. Taking up-slope and downward respectively as positive,Eliminate the common tension to obtainHere $\theta =10^{\circ }$, $\mu =0.1$ and $a=1.60\mathrm{m}{\mathrm{s}}^{-2}$. The pulley changes the direction of the string force; in the ideal model it does not change its magnitude.