Let r be the electron-nucleus separation and use the reduced mass μ=meM/(me+M). Coulomb attraction supplies the relative centripetal force, and Bohr quantization fixes the relative angular momentum:Eliminating v givesThe total energy is E=μv2/2−Ze2/(4πϵ0r)=−Ze2/(8πϵ0r), henceHere a0 is the ordinary Bohr radius and R∞ the infinite-nuclear-mass Rydberg constant. The electron's radius about the centre of mass is Mrn/(M+me); for a heavy nucleus this distinction and the reduced-mass correction are small, but the supplied nuclear mass permits them to be stated precisely.
rμv2=4πϵ0r2Ze2,μvr=nℏ.
rn=μZe24πϵ0ℏ2n2=a0μmeZn2.
En=−2(4πϵ0)2ℏ2n2μZ2e4=−hcRMn2Z2,RM=R∞meμ.
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