Put β=mα/ℏ2. The delta interaction reduces the integral equation to ψs=eikx+iβeik∣x∣ψs(0)/k. At zero, ψs(0)=(1−iβ/k)−1. HenceTheir sum is one, as required for a real potential. The explicit wave is the indicated incident-plus-reflected form for x<0 and teikx for x>0; it is continuous and has derivative jump −2βψ(0).
t=k−iβk,r=k−iβiβ,T=k2+β2k2,R=k2+β2β2.
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