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Quantum virial theorem
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Past exam of the physics course of the year 4 of the natural sciences course of the University of Cambridge
/
2016
/
Paper 1
/
Section B
/
B7
/
b
/
Solution
2026-10-20
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Orthogonality
gives
⟨
a
^
+
2
⟩
=
⟨
a
^
−
2
⟩
=
0
, while the ladder
coefficients
give
⟨
a
^
+
a
^
−
⟩
=
n
and
⟨
a
^
−
a
^
+
⟩
=
n
+
1
. Squaring the expressions for
x
^
and
p
^
therefore gives
⟨
x
2
⟩
=
mω
ℏ
(
n
+
2
1
)
,
⟨
p
2
⟩
=
m
ℏ
ω
(
n
+
2
1
)
.
(1)
Thus
⟨
V
⟩
=
2
1
m
ω
2
⟨
x
2
⟩
=
2
1
ℏ
ω
(
n
+
2
1
)
,
⟨
K
⟩
=
2
m
⟨
p
2
⟩
=
2
1
ℏ
ω
(
n
+
2
1
)
.
(2)
Their equality is the
harmonic-potential
case of the
quantum virial theorem
, and their
sum
is the
oscillator
energy
E
n
=
ℏ
ω
(
n
+
1/2
)
.
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