Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 1 24F b Solution Created 2026-09-24 Updated 2026-09-29
Homogenizing the affine equation gives the projective closureThis is the Klein quartic. It is smooth: if all three projective partial derivatives vanished, thenMultiplying them gives . If one coordinate is zero, the displayed equations force all three to vanish, which is impossible in projective space. Thus is a smooth compactification of . The smooth compactification compatible with the extended coordinate functions is its normalization, and since is already smooth it is biholomorphic to .
For a direct genus computation, consider the extended coordinate map . A generic leaves the cubic equationso . In the affine part, ramification occurs where . Solving gives and the seven pointsAt the origin, , so the ramification index of a holomorphic map is three and the contribution is two. At each of the other seven points, , , and , so the ramification index is two and each contributes one.
There are two points at infinity. Near , in coordinates , , the equation isand , so is unramified. Near , in coordinates , , the equation isThus and , so has ramification index two and contributes one. The total ramification is thereforeThe Riemann-Hurwitz formula for the degree-three map to the sphere givesand henceThis also agrees with the genus of a smooth plane curve of degree four.
Past exam of the mathematics course of the University of Cambridge 2020 ii Paper 1 24F Solution Created 2026-09-24 Updated 2026-09-29
Let be a nonconstant holomorphic map of degree between compact connected Riemann surfaces. At , let be the ramification index of a holomorphic map. Choose a triangulation of containing every branch value among its vertices, and lift it to .
If the target triangulation has vertices, edges, and triangles, then the lifted triangulation has edges and triangles, because no branch value lies in an edge or face interior. For a target vertex , local degree counting givesConsequently the number of vertices above isWriting , the Euler characteristic is thereforeSince a compact orientable surface of genus has Euler characteristic , this Triangulation proof of the Riemann-Hurwitz formula givesor equivalently
Now extend a cubic polynomial to a degree-three holomorphic mapof the Riemann sphere. Both genera are zero, so Riemann--Hurwitz givesThe point at infinity is totally ramified with , contributing two. Thus the finite points contribute exactly two. There are consequently two cases.
If there is one finite ramification point , it has index three. Choose an affine source map sending zero to . Thenfor some , and integration givesAn affine target map subtracts and rescales by , yielding .
Otherwise there are two distinct finite ramification points, each of index two. Choose an affine source map sending and to them. The derivative of is then a nonzero multiple of :HenceThe affine target map givesTherefore the affine normal forms of a complex cubic polynomial are precisely
Past exam of the mathematics course of the University of Cambridge 2020 ii Paper 2 23F Solution Created 2026-09-24 Updated 2026-09-29
In local coordinates centred at and , a nonconstant rational map has the formThe point is a ramification point of a holomorphic map when its ramification index of a holomorphic map satisfies . A branch value of a holomorphic map, also called a branch point in the target, is a value of some ramification point.
Let be the finite set of branch values and put . For every , all points of have local degree one, so the holomorphic inverse function theorem supplies disjoint neighbourhoods on which is biholomorphic. Compactness of the fibre lets their target neighbourhoods be intersected to one evenly covered neighbourhood of . Henceis an unramified covering map. Here the displayed restriction requires ; if “ramification point” is reserved only for points with , then the source deletion must be written .
The Monodromy theorem says that analytic continuations along endpoint-fixed homotopic paths have the same terminal germ. Equivalently here, the path lifting theorem lifts a loop based at from each point of ; taking the endpoint of each lift permutes that fibre. The permutation depends only on , giving the monodromy group of a covering.
For the stated function, make the Möbius change of coordinateThenThe critical points are , with branch valuesA loop around interchanges the two roots born from , so its branch cycle is a transposition. A loop around simultaneously interchanges the two pairs that collide there, so its branch cycle is a product of two disjoint transpositions. With a suitable labelling these areThey generate a transitive group of order eight; their product is a four-cycle. Therefore the full monodromy group isthe dihedral group in its action on the four vertices of a square.