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For positive integers $r,k,m$, there is $n$ such that every $k$-coloring of the $r$-element subsets of $[n]$ has a monochromatic $m$-element subset. A diagonal compactness argument deduces this from Ramsey's theorem.

Ramsey's theorem for $r$-sets says that every finite coloring of $[\mathbb{N}{]}^{(r)}$ has an infinite monochromatic set. We prove it by mathematical induction on $r$. The case $r=1$ is the infinite pigeonhole principle. Suppose the result holds for $r-1$, and let $c:[\mathbb{N}{]}^{(r)}\to [k]$. Choose $a_1$, then use the induction hypothesis on the coloring $F\mapsto c(F\cup \{a_1\})$ to obtain an infinite set $M_1$ on which this color is constant, say $d_1$. Inductively chooseso that $c(F\cup \{a_j\})=d_j$ for every $F\in [M_j{]}^{(r-1)}$. Some color $d$ occurs for infinitely many $d_j$. If $j_1<j_2<\cdots$ are the corresponding indices, every $r$-set from $\{a_{j_1},a_{j_2},\dots \}$ has color $d$: take its least-indexed element $a_{j_s}$, after which its other $r-1$ elements lie in $M_{j_s}$. This proves the theorem.

Solved by gpt-5.6-sol high.

Suppose the Finite Ramsey theorem failed for fixed positive integers $r,k,m$. For every $n$ choose a $k$-coloring $c_n:[n{]}^{(r)}\to [k]$ with no monochromatic $m$-set. There are only finitely many colorings of $[r{]}^{(r)}$, so an infinite subsequence of the $c_n$ agrees there. Pass to a further infinite subsequence agreeing on $[r+1{]}^{(r)}$, and continue. The diagonal argument produces compatible colorings $d_N:[N{]}^{(r)}\to [k]$ such that $d_{N+1}{|}_{[N{]}^{(r)}}=d_N$ and no $d_N$ has a monochromatic $m$-set.

Define $d(F)=d_N(F)$ whenever $N\ge \max F$. Compatibility makes this a well-defined finite coloring of $[\mathbb{N}{]}^{(r)}$. By Ramsey's theorem it has an infinite monochromatic set, whose first $m$ elements contradict the defining property of a sufficiently large $d_N$. This compactness argument proves the finite statement.

Solved by gpt-5.6-sol high.

Let $c:\mathbb{N}\to [k]$ be the given finite coloring. Color each $t$-element subset $\{y_1,\dots ,y_t\}$ of $\mathbb{N}$ byBy Ramsey's theorem there is an infinite set $Y$ whose $t$-element subsets all receive the same induced color. Enumerate it increasingly as $x_1<x_2<\cdots$. Then every sum $x_{i_1}^2+\cdots +x_{i_t}^2$ with $i_1<\cdots <i_t$ has that color. The argument works for every positive integer $t$; primality is not needed for this part.

Solved by gpt-5.6-sol high.

Given a finite coloring $c:\mathbb{N}\to [k]$, color each three-element subset $\{a<b<d\}$ by the color ofRamsey's theorem gives an infinite set $M$ on whose triples this induced coloring is constant. Enumerating $M$ increasingly as $x_1<x_2<\cdots$ gives a strictly increasing sequence for which every $x_i+2x_j+3x_k$, $i<j<k$, has the same color.

Solved by gpt-5.6-sol high.