Reaction formula-unit conservation

For $A\rightleftharpoons 2B$, the conserved amount is $M=N_A+N_B/2$. The total particle count $N_A+N_B$ changes during reaction. Defining a dissociated fraction by $\alpha =N_B/(2M)$ gives $N_A=M(1-\alpha )$.

For $A\rightleftharpoons 2B$, ${\alpha }^2/(1-\alpha )=K_N/(4M)$. The left side increases monotonically on $0<\alpha <1$, so increasing the conserved formula-unit density at fixed temperature reduces dissociation in the ideal model.