Two distinct circles are tangent when they meet at exactly one point. For external tangency the distance between centers is the sum of the radii; for internal tangency it is their absolute difference. These relations turn many circle packing problems into exact distance equations.
Four positive-radius circles with pairwise disjoint interiors, successive external tangencies, and four distinct contact points have those contact points on a circle. Apply the reciprocal Möbius transformation at one contact . The two circles through become disjoint parallel lines; the other two disks lie between them and avoid zero. Collinearity for tangent circles between parallel lines places the three finite transformed contacts on a straight line. That straight line misses zero: otherwise its segment across the strip would pass through zero, while that segment is contained in the two transformed closed disks. Its inverse is therefore a genuine circle through , containing all four original contacts. Allowing internal tangency without the pictured disjoint-interior hypotheses admits collinear degeneracies instead.
Let two positive-radius circles have external tangency at and lie in the closed strip between two parallel lines, touching opposite boundaries at . Then are collinear. To prove this, choose coordinates with the boundaries , put and , and write the centres as , . The contact point isThe closed line segment is contained in the union of the two closed disks: its portions from to and from to are chords. The strip and external tangency hypotheses are essential to this particular formulation.
Articles by others on the same topic
There are currently no matching articles.