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An additive tare device is a tare device that can establish a zero indication with a load present without reducing the weighing range available for net loads.^[ref] The supported container still contributes tare mass; the instrument provides a separate tare allowance rather than obtaining extra capacity simply by changing a displayed number.

Consider a deliberately specified model with maximum weighing capacity $\mathrm{Max}=5\mathrm{kg}$ for net loads and a maximum additive tare allowance $T_{\mathrm{add}}=2\mathrm{kg}$. Assume these ranges are available together for the stated configuration:A container with tare mass $T=1.2\mathrm{kg}$ can then accompany net mass $N=5\mathrm{kg}$, giving gross mass $G=6.2\mathrm{kg}$. The model's full combined boundary is $7\mathrm{kg}$ when both allowances are used. These numbers are chosen examples, not specifications for a particular scale.

By comparison, a subtractive tare device with a $5\mathrm{kg}$ gross-load budget would leave only $3.8\mathrm{kg}$ for net mass after the same $1.2\mathrm{kg}$ container is tared. Both displays can initially read zero; their available net-load capacities differ.

The OIML definition of maximum weighing capacity explicitly omits additive tare capacity, while its maximum-tare-effect terminology records the tare device's capacity separately.^[ref] A complete load description therefore identifies the container's tare mass, the desired net mass and the instrument's declared tare allowance. The load receptor continues to carry their combined physical load.

Gross mass is the mass of the complete specified load, including its contents and the packaging counted as tare mass. For that same boundary,The gross indication in OIML's weighing terminology is obtained with neither a tare device nor a preset tare device operating, after an initial zero indication.^[ref] A full crate's gross mass consequently differs from an individual jar's gross mass, because the specified loads differ.

Consider four jars, each containing $0.50\mathrm{kg}$ of material and having an empty-container tare mass of $0.20\mathrm{kg}$. An outer crate adds $0.80\mathrm{kg}$. For the complete load, the net mass of the contents, composite tare mass, and gross mass are respectivelyThese are chosen bookkeeping values, assuming the listed components exhaust the load and each component is counted once.

Subtracting the full composite tare mass from the complete gross mass gives $3.60-1.60=2.00\mathrm{kg}$ of contents. If the jars' $0.80\mathrm{kg}$ has already been removed from an intermediate total, subtracting the same full composite tare mass again gives $1.20\mathrm{kg}$. The missing $0.80\mathrm{kg}$ is precisely the duplicated deduction. Use one load boundary and subtract each packaging component once.

The gross mass also remains relevant to maximum weighing capacity when a subtractive tare device reduces the available net-load range.^[ref] For an illustrative instrument modeled with a $1.000\mathrm{kg}$ gross-load limit, a $0.120\mathrm{kg}$ container leaves $0.880\mathrm{kg}$ for contents. At that limit the complete load still has gross mass $1.000\mathrm{kg}$, even though the tared display reports only its contents.

For a stationary ideal weighing scale, the normal contact force associated with a complete load is related to its gravitational weight. A displayed net mass is a processed indication of that load; it is not the full supported mass. Changes in the gravitational field, measurement calibration, or the load boundary must therefore be distinguished when interpreting a reading.

A load receptor is the part of a weighing scale intended to receive the load, such as the platform supporting a parcel. The instrument can transmit that load's force to a separate measuring element, for example a load cell.^[ref]

A simple static model explains why the physical support path matters. Suppose a $2\mathrm{kg}$ object rests entirely on a horizontal load receptor, with local gravitational acceleration $g=9.8\mathrm{m}{\mathrm{s}}^{-2}$. Neglecting air buoyancy, its gravitational weight is $19.6\mathrm{N}$. The instrument can convert the measured supporting force into a mass indication through its calibration.

Now arrange a separate overhead support to carry $4.9\mathrm{N}$ of the same object's gravitational weight, while the rest still reaches the load receptor. The scale then supports $14.7\mathrm{N}$ and, under the same ideal calibration, indicates $1.5\mathrm{kg}$. The object's mass remains $2\mathrm{kg}$: the indication changed because the support path changed. This is an illustrative static equilibrium experiment, rather than a claim about any instrument's specified error.

A removable container placed on the platform contributes tare mass; it is distinct from the instrument's own load receptor. To measure the net mass of the contents, the tare device changes the indicated reference while the receptor continues to carry both container and contents. Contact with an external support can therefore defeat an otherwise correct subtraction.

The maximum weighing capacity, conventionally $\mathrm{Max}$, specifies the upper capacity of a weighing scale; the OIML definition excludes additional capacity provided by an additive tare device.^[ref] A display reset does not by itself establish a new physical load capacity.

For a chosen model with a subtractive tare device, let $\mathrm{Max}=5\mathrm{kg}$ and suppose the combined gross mass on the load receptor must satisfyA container with tare mass $1.2\mathrm{kg}$ leaves at most $3.8\mathrm{kg}$ for net mass. Pressing the tare device can make the display read zero with that container present, but the container remains part of the supported mass. This calculation assumes the stated subtractive-tare model; it does not assign the same capacity budget to a scale with an additive tare device.

The maximum safe load describes a different boundary: the static load an instrument can carry without permanently changing its metrological qualities. It does not define the upper end of its specified weighing capacity.^[ref] For example, an instrument could have a declared $\mathrm{Max}$ of $5\mathrm{kg}$ and a separately declared maximum safe load of $7\mathrm{kg}$. Those hypothetical markings would not turn a $6\mathrm{kg}$ indication into a measurement within the declared $5\mathrm{kg}$ weighing capacity.

A preset tare device subtracts a preset tare value from a measured gross or net indication and displays the calculated result.^[ref] A stored container value can therefore be reused without weighing each empty container individually.

Suppose a container and its contents have measured gross mass $G=2.30\mathrm{kg}$ and the entered preset tare value is $PT=0.30\mathrm{kg}$. Subtraction gives a calculated net mass of $2.00\mathrm{kg}$. If this particular container actually has tare mass $T=0.34\mathrm{kg}$, however, its contents have mass $1.96\mathrm{kg}$. Even an otherwise exact gross measurement would then overestimate the contents by $0.04\mathrm{kg}$.

The error follows without any instrument-specific assumption:A mismatch in the entered container value passes directly into the result. Reusing one value for nominally identical containers is therefore an assumption about their tare masses, rather than a new measurement of each container.

The starting indication also matters. If an ordinary tare device has already removed a $0.30\mathrm{kg}$ container contribution, the displayed $2.00\mathrm{kg}$ is already net for that reference. Subtracting the same $0.30\mathrm{kg}$ again would give $1.70\mathrm{kg}$. A deliberate second subtraction can represent another distinct component, but applying the same container correction twice is a different calculation from removing its tare mass once.

A preset tare value is a numerical tare mass entered or recalled for use in subsequent weighings without individually determining each container's tare. The pinned OIML terminology denotes it by $\mathrm{PT}$ and calls the measured gross or net indication minus this value a calculated net value. It can be supplied through a preset tare device rather than obtained by weighing the current empty container.^[ref]

For an original example, a stored container tare is $\mathrm{PT}=250\mathrm{g}$, but the actual empty container has tare mass $T=263\mathrm{g}$. Adding $500\mathrm{g}$ of material gives gross mass $G=763\mathrm{g}$. Applying the stored value givesalthough the actual net mass is $N=G-T=500\mathrm{g}$. Their difference isAn underestimated preset tare therefore overestimates the contents. Repeating the same discrepancy across ten containers produces a $130\mathrm{g}$ total discrepancy; more displayed digits do not remove it.

A useful physical check independently weighs representative empty containers, including the same lids and attachments used during the loaded measurement, and compares them with the stored value. Record which load components the preset represents. If it is subtracted from an indication that has already had those components removed by a tare device, the same tare mass is deducted twice. The stored number's provenance and variability belong in the measurement model and its measurement uncertainty.

A subtractive tare device is a tare device whose operation reduces the weighing range available for net loads.^[ref] Its zero display accounts for a load already present, while that load continues to occupy part of the instrument's capacity.

Consider a chosen model with maximum weighing capacity $\mathrm{Max}=10\mathrm{kg}$ and no additive tare capacity. If a container of tare mass $T$ is supported on the load receptor, the admissible net mass $N$ in this model satisfiesWith $T=2.5\mathrm{kg}$, the largest net load in this capacity budget is $7.5\mathrm{kg}$. Adding $8\mathrm{kg}$ after taring would produce gross mass $10.5\mathrm{kg}$, even though the desired net indication is below $10\mathrm{kg}$.

Changing to a $0.8\mathrm{kg}$ container would leave $9.2\mathrm{kg}$ available for net mass in the same model. This is a physical consequence of reducing the supported tare mass, rather than a benefit obtainable by repeatedly resetting the display.

An additive tare device is defined by retaining the net-load weighing range. Therefore the equation above is a model for subtractive tare and a shared gross-load bound, rather than a universal rule that every scale's printed $\mathrm{Max}$ includes every possible tare allowance. The chosen container, allowed tare range and instrument capacity must describe the same load configuration.

A tare device establishes a zero indication on a weighing scale while a load remains on its load receptor. An additive tare device preserves the weighing range for net loads; a subtractive tare device reduces that range.^[ref]

For example, place an empty $0.40\mathrm{kg}$ container on the load receptor and operate the tare device. The display reads zero even though the scale still supports the container. Adding $1.10\mathrm{kg}$ of material gives gross mass $1.50\mathrm{kg}$ and, ideally, an indicated net mass of $1.10\mathrm{kg}$. Removing both material and container without clearing the tare would ideally give $-0.40\mathrm{kg}$. This negative indication is consistent with the changed reference.

The cancellation can be seen in a linear model. If the unrounded indication before tare is $r(m)=am+b$, and the supported container has tare mass $T$, the indicated result after adding net mass $N$ isThe additive offset $b$ and the container contribution cancel. A response scale factor $a\ne 1$ remains, so taring alone does not establish calibration across the load range.

The container's physical load remains on the scale after taring. Consequently the available maximum weighing capacity depends on the kind of tare device, even when two instruments show the same zero. A preset tare device performs a related numerical subtraction using an entered or recalled value, rather than necessarily measuring this particular empty container.

Tare mass is the specified container or packaging mass excluded when reporting net mass. It is also called tare weight in weighing terminology. The intended boundary matters: a jar alone and that jar with its lid have different tare masses. A tare device adjusts a weighing scale's indication with a load present, whereas a zero-setting device establishes zero with the load receptor unloaded.^[ref]

A simple demonstration separates the reading from the physical load. Choose an empty container of mass $m_{\mathrm{t}}=0.120\mathrm{kg}$ and an ideal weighing scale that initially reads zero. After the container is placed on the load receptor, operate the tare device. Its displayed value becomes zero while the container's mass remains $0.120\mathrm{kg}$. In a uniform gravitational field with chosen magnitude $g=9.81\mathrm{m}{\mathrm{s}}^{-2}$, its gravitational weight is stillThe supporting force remains present after the display adjustment.

In an ideal unit-gain measurement model, the tared indication for a complete load of mass $m$ is $I(m)=m-m_{\mathrm{t}}$. Adding $0.300\mathrm{kg}$ of contents gives gross mass $0.420\mathrm{kg}$ and indication $0.300\mathrm{kg}$. Removing the complete load while retaining that reference gives indication $-0.120\mathrm{kg}$. The negative indication expresses the difference from the stored reference; the removed container still has positive mass.

A preset tare device instead uses an introduced preset tare value, which can be recalled or entered without weighing each individual empty container.^[ref] For the same chosen load, using a preset of $0.100\mathrm{kg}$ gives calculated net mass $0.420-0.100=0.320\mathrm{kg}$: the contents are overestimated by 20 g. A persistently low preset produces a systematic error even with otherwise exact readings.

Composite tare mass includes several excluded components, such as all the jars and an outer crate. The gross mass example shows how to account for these components once each. The symbol $m_{\mathrm{t}}$ here denotes a mass; the terminology's use of the word weight does not change the quantity's unit from a kilogram to a unit of force.

A zero-setting device makes a weighing scale indicate zero with no load on its load receptor.^[ref] A tare device instead establishes a zero indication with a load present. This difference identifies which physical reference the instrument is being asked to use.

For an illustrative linear response, write the unrounded mass indication aswhere $m$ is the applied mass, $a$ is the response scale factor and $b$ is an additive offset. An ideal zero adjustment subtracts the unloaded indication $r(0)=b$, givingIf $a=1.01$ and $b=0.03\mathrm{kg}$, a true $1\mathrm{kg}$ load initially indicates $1.04\mathrm{kg}$ and indicates $1.01\mathrm{kg}$ after this zero adjustment. The $0.03\mathrm{kg}$ offset has disappeared, while the proportional measurement error remains. Correct zero does not establish correct response at other loads; a calibration using known nonzero loads tests that additional question.

A practical observation follows directly from the model: record the empty indication, apply a known load, remove it and check the empty indication again. Agreement at zero tests the reference return, while agreement under load also tests the response away from zero. Instrument-specific zero-setting limits still govern actual operation; the algebra describes an ideal offset correction rather than a replacement for those limits.