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Use $B^0=d\bar{b}$ and ${\bar{B}}^0=\bar{d}b$. A box Feynman diagram with two W bosons and internal up-type quarks changes one neutral flavour into the other. The top quark contribution dominates the dispersive mixing amplitude and carries the squared CKM combination involving $V_{td},V_{tb}$. With a consistent meson phase convention,The illustration in b shows this box and the dominant decay topology. A suitable common final state is $f=J/\psi K_S$, reconstructed for example through $J/\psi \to {\mu }^{+}{\mu }^{-}$ and $K_S\to {\pi }^{+}{\pi }^{-}$. The leading $\bar{b}\to \bar{c}c\bar{s}$ tree transition gives $B^0\to J/\psi K^0$, while the conjugate gives ${\bar{B}}^0\to J/\psi {\bar{K}}^0$. Neutral kaon mixing projects both kaon flavours onto the observed $K_S$.

The final state is approximately a CP eigenstate with ${\eta }_f=-1$: $J/\psi$ and $K_S$ each have CP approximately $+1$, and their relative orbital angular momentum is $L=1$ to couple the vector charmonium to the spin-zero parent. Neglecting the small kaon CP impurity and subleading decay amplitudes,There are two indistinguishable paths, direct decay and mixing followed by decay, so their amplitudes interfere. For $\Delta {\Gamma }_d\simeq 0$ and negligible direct CP violation, the time-dependent neutral-B CP asymmetry isMeasure the production flavour and proper decay time, fit the oscillation coefficient, and extract $\sin 2\beta$. This determines $\beta$ up to the usual trigonometric ambiguities unless further information is used. The cancellation of the dominant decay phase is why this channel isolates the angle involving $V_{td}$ without needing $V_{ub}$.

In gluon-fusion Higgs production, two gluons couple to a closed top quark loop, and the Higgs boson couples to that massive quark through its Yukawa interaction. The right panel of the diagram in c shows one explicit colour-flow component: internal $t_r\to t_b$ at one gluon insertion, then $t_b\to t_r$ at the other; the colour-neutral Higgs boson insertion preserves the internal color charge. Include both loop orderings. The color charge factor isso the two incoming gluons are projected onto a colour singlet. The Yukawa coupling is $y_t=\sqrt{2}{m}_t/v$, and the $h\bar{t}t$ vertex has strength $m_t/v$. No direct tree-level $hgg$ mass coupling is needed. Integrating out a sufficiently heavy top quark generates an effective interaction proportional to $(h/v)G_{\mu \nu }^a{G}^{a\mu \nu }$, which is allowed by gauge invariance even though the gluon is massless.

There is also no kinematic obstacle: two massless particles with nonparallel momenta can have nonzero total invariant mass. In particular, head-on gluons have $\hat{s}=4E_1{E}_2$, providing the energy needed for the Higgs boson at the LHC.

Here $x=m_W^2/m_t^2$, and the tree-level decay width neglects the bottom quark mass. The open two-body W channel gives a top quark lifetime of a few $10^{-25}\mathrm{s}$, shorter than the hadronization time. A fifth-power Sargent's rule extrapolation misses this physical regime.^[ref]