Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 305 3 b Solution Created 2026-10-03 Updated 2026-10-06
The tree-level Feynman diagram contains one weak charged current vertex. Fermion arrows point along fermion-number flow, so the outgoing antiquark arrow points toward the vertex.
For one fixed matching color, the scattering amplitude isAn overall phase from the vertex has no effect on the width. The fermion spin sums give , in the massless approximation. For the three initial polarizations, use a spin average of . The gamma matrix trace identities giveThe sign of the last term follows the PDF's convention and does not affect this decay: the polarization sum is symmetric. Since and the daughter masses vanish, and . ThereforeIn the rest frame, the two-body Lorentz-invariant phase space integrates to : after the spatial delta function sets , its radial delta function fixes . Explicitly,The decay formula consequently givesThis is the printed expression, interpreted for one color. For a physical quark-flavor channel there are three orthogonal final color states. Their probabilities add; no initial color average is present for a colorless W boson. ThusThe PDF's formula omits this color multiplicity if read as the ordinary inclusive flavor width. It is also the familiar normalization for a colorless lepton channel.
The six physically accessible quark combinations are . A real on-shell W boson cannot produce a top quark; the massless approximation is applied to the accessible daughters and does not open a physically forbidden top channel. CKM matrix unitarity gives . Therefore the physical color-summed hadronic width at this order isIf the printed one-color convention is retained for every channel, its sum is instead . In the artificial theory where all three up-type flavors, including the top, are kinematically massless, there would be nine channels and the physical sum would be ; that is not the on-shell Standard Model channel list.
