Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 32 2 b Solution Created 2026-10-03 Updated 2026-10-06
In a time-homogeneous continuous-time Markov chain, a state's holding time is exponential with rate equal to its total outgoing transition intensity. Converting the specified times to months givesThe exit-type probability follows by dividing its transition intensity by the total exit rate. ThereforeThese are starting values for numerical estimation, rather than further observations or constraints on the final fitted rates.
Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 32 2 e Solution Created 2026-10-03 Updated 2026-10-06
In the log-linear transition intensity model, each hazard ratio multiplies a specific off-diagonal transition intensity, comparing its post-transplant period with the pre-transplant period while holding the modeled origin state fixed. Diagonal entries must then be recalculated from row sums.
For mild-to-severe progression, the early hazard ratio suggests a 48% decrease, but its interval includes no effect. The later hazard ratio , with interval wholly below one, suggests a 98% decrease. These findings are compatible with suppression of progression by hematopoietic stem cell transplantation among those remaining in the mild state.
For mild-to-death, the early hazard ratio indicates a very large relative increase, and the later ratio still indicates an increase; both intervals are above one. For severe-to-death, the early ratio indicates increased mortality, whereas the later ratio indicates a 43% decrease; these intervals also exclude one. Early treatment toxicity and infection are plausible explanations for an immediate mortality increase. Later control of the underlying myelodysplastic syndrome is a plausible explanation for reduced advanced-state mortality and progression.
Relative increases must be interpreted alongside baseline rates. The early mild-state death rate is approximately per month, whereas the early severe-state death rate is per month. Thus the far larger mild-state hazard ratio partly reflects its much smaller starting mortality, rather than greater absolute mortality after transplantation. The later corresponding rates are and per month.
Within the question's model, delaying transplantation while the disease is mild can avoid a large immediate mortality cost, whereas the high baseline mortality in the severe state makes the later survival benefit more valuable. This provides a qualitative rationale for the stated policy. The estimates do not establish an optimal timing rule: treatment selection, changing health status, selection of survivors into the later period and the use of the previous visit's covariate value can affect the comparison. They are associations from the fitted cohort model, not automatically causal hazard ratios.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 207 2 a Solution Created 2026-10-03 Updated 2026-10-14
Use three states of a continuous-time Markov chain: disease-free , pre-clinical , and clinical . The transition intensities are for onset and for progression. Clinical disease is an absorbing state. The mandatory pre-clinical phase excludes a direct jump, and this untreated progression model has no reverse transitions.
With row-vector probabilities and state order , the generator matrix isIts rows sum to zero, so only the two off-diagonal transition intensities are unknown. This is a continuous-time multi-state model with sequential irreversible progression.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 207 2 c Solution Created 2026-10-03 Updated 2026-10-06
Assume the 1000 individuals are initially disease-free. The event being counted is onset during the ten-year period, not occupancy of the pre-clinical state at its end. Using the estimated transition intensity as a constant onset rate and linearity of expectation, the expected number of onsets isThe first-order approximation is close, but does not account for depletion of the disease-free group.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 207 3 a Solution Created 2026-10-03 Updated 2026-10-14
In the SIR model, count susceptible, infectious, and recovered immune individuals. The closed population has . Under homogeneous mixing, use the paper's mass-action infection convention: each susceptible has infection hazard function , so the population infection rate is . Each infectious individual recovers with hazard function , giving population recovery rate and mean infectious duration .
The arrows are one-way: recovered individuals are immune, and there are no demographic entries or exits. The transition intensities attached to the arrows are population flow rates, rather than individual hazard functions.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 207 3 g Solution Created 2026-10-03 Updated 2026-10-06
Initially, the infection and recovery transition intensities are and . By competing exponential clocks, the first-event waiting time has distribution
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 207 3 c i Solution Created 2026-10-03 Updated 2026-10-05
For a treated patient the recovery transition intensity is per year. A symptoms spell is a holding time with an exponential distribution of rate , soThe treatment multiplier for onset affects how often symptoms begin, not the duration of a spell once the patient is in state 2, under this homogeneous continuous-time Markov chain.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 207 1 a iii Solution Created 2026-10-03 Updated 2026-10-05
For , the Markov property and the definition of transition intensity giveSumming over the possible pre-jump states gives the density of the expected Markov-chain entry count:For a finite-state continuous-time Markov chain, the chance of two or more jumps in this short interval is . There is no contribution: diagonal entries of the infinitesimal generator encode exit rates, not jumps into the same state. With repeated entries possible, this density is an expected event rate rather than the probability density function of a single normalized random time.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 207 1 a iv Solution Created 2026-10-03 Updated 2026-10-05
Integrate the expected Markov-chain entry count density and use the occupation time of a continuous-time Markov chain formula:Each term is a transition intensity multiplied by the expected exposure time to that transition. This counts every entry, including returns, rather than only the first visit. For countably many states the same nonnegative interchange follows from Tonelli theorem, provided the resulting expected count is finite. The sum excludes .
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 207 1 b ii Solution Created 2026-10-03 Updated 2026-10-05
The four-parameter panel-observed multi-state likelihood requires the following additional assumptions.
- Irreversibility: the chronic disease can progress but cannot improve, so and state 3 is absorbing. Merely permitting transitions between adjacent states does not impose this; allowing regression would require additional transition intensities.
- Piecewise-constant age: the current age is held at 50 and 55 over the respective observation intervals. Actual age changes continuously, and a five-year interval can be too long for this approximation when the age effect is substantial.
- Log-linear age effects and common rates: the specified age functions apply to the patient, without unmodelled heterogeneity or other changing covariates.
- Observation mechanism: disease states are recorded without misclassification, and examination times or dropout carry no additional information about the underlying process once the modelled history is given. A new visit only one year after a five-year gap might have been prompted by worsening symptoms, making the observation schedule informative.
If age is instead updated continuously, the model is time-inhomogeneous and the displayed homogeneous transition formula is not exact. For example, setThen the exact irreversible likelihood contribution isThus the simple closed form uses an explicit frozen-age approximation; adjacency alone and continuously evolving age do not determine that form.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 207 1 b i Solution Created 2026-10-03 Updated 2026-10-05
Use an irreversible continuous-time multi-state model , with state 3 absorbing. Let and , and define log-linear age effects byFor a closed-form panel-observed multi-state likelihood, freeze the age covariate at the start of each observation interval. The transition intensities are then over the first interval and over the second. Conditional on the initial state, the likelihood contribution isIndeed, and . In this irreversible continuous-time Markov chain, the intermediate state has probabilityThe second expression is the continuous limit of the first and handles equal rates. The observed two-state jump across an interval is compatible with adjacent instantaneous transitions: an unobserved visit to state 2 occurs between the examinations.
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 207 1 c Solution Created 2026-10-03 Updated 2026-10-05
Under the frozen-age exponential distribution convention, the mean waiting time is the reciprocal of the outgoing transition intensity. The beliefs therefore specifyBoth rates double over ten years. ConsequentlyThese calibrate the age-specific constant-rate means; they are not exact mean ages of future events when age-dependent rates continue increasing throughout the waiting time.
For a literal continuously ageing interpretation, a rate gives a Gompertz distribution for the waiting time. For , its mean isHere is the exponential integral. Solving and , and the analogous pair with means 2 and 1, instead giveswith rates and slopes in inverse years. These are an alternative continuous-age calibration, not the frozen-age answer boxed above.
Past exam of the mathematics course of the University of Cambridge 2023 iii Paper 207 3 b Solution Created 2026-09-28 Updated 2026-10-14
Let denote the Transition semigroup of a continuous-time Markov chain. The first person is observed in at day zero, at day seven, and at day fourteen, so the contribution is
For the second person, death is observed exactly at day six but the infection time is latent. The density of an transition at day six isThus the combined contribution is a function of . This illustrates how panel observations contribute transition probabilities while an exactly observed transition contributes a state probability times its transition intensity.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 207 1 d Solution Created 2026-09-24 Updated 2026-09-25
Use a three-state continuous-time multi-state model with transient infected state and absorbing recovered and dead states and . If recovery and death have constant transition intensities and , its Q-matrix iswith state order . This is also a competing risks model: recovery and death are the two mutually exclusive first events.

