Ciro Santilli @cirosantilli 37

The relatively large Sainsbury's located at 42-45 Sidney St, Cambridge CB2 3HX. Existed in late 2010's and early 2020's Ciro Santilli witnessed.

Being the only relatively large grocery shop in central Cambridge near several colleges, where manu students live, makes this one of the most popular grocery shopping location for many of the students.

The Oxford equivalent has to be the Tesco Express on Magdalen St, Oxford OX1 3AD, but not sure if there's a name for it.

Bibliography:

Whatever it is that biology studies.

A convex regular polyhedron.

Their beauty is a classification type result as stated at classification of regular polytopes.

The basic intuition for this is to start from the origin and make small changes to the function based on its known derivative at the origin.

More precisely, we know that for any base b, exponentiation satisfies:And we also know that for $b=e$ in particular that we satisfy the exponential function differential equation and so:One interesting fact is that the only thing we use from the exponential function differential equation is the value around $x=0$, which is quite little information! This idea is basically what is behind the importance of the ralationship between Lie group-Lie algebra correspondence via the exponential map. In the more general settings of groups and manifolds, restricting ourselves to be near the origin is a huge advantage.

Now suppose that we want to calculate $e^1$. The idea is to start from $e^0$ and then then to use the first order of the Taylor series to extend the known value of $e^0$ to $e^1$.

E.g., if we split into 2 parts, we know that:or in three parts:so we can just use arbitrarily many parts $e^{1/n}$ that are arbitrarily close to $x=0$:and more generally for any $x$ we have:

Let's see what happens with the Taylor series. We have near $y=0$ in little-o notation:Therefore, for $y=x/n$, which is near $y=0$ for any fixed $x$:and therefore:which is basically the formula tha we wanted. We just have to convince ourselves that at ${\lim }_{n\to \infty }$, the $o(1/n)$ disappears, i.e.:

To do that, let's multiply $e^y$ by itself once:and multiplying a third time:TODO conclude.