Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-oxford/2015/prelims/mathematics-iii/1/a/solution

The integrating factor for this linear ordinary differential equation is . Multiplication gives an exact derivative:
Consequently . The initial condition gives , so the initial value problem has solution
The integrating factor calculation determines every solution, and the initial condition fixes its remaining constant of integration uniquely.

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