Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 2 38B b Solution Created 2026-09-24 Updated 2026-09-25
For an affine parameter , the geodesic equation and the connection coefficients from part (a) givewhere dots denote derivatives with respect to .
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 115 4 a Solution Created 2026-09-24 Updated 2026-10-03
For local coordinates , a curve is an affinely parametrized geodesic exactly when it satisfies the geodesic equationwhere the Christoffel symbols of the Levi-Civita connection are
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 115 4 c Solution Created 2026-09-24 Updated 2026-09-25
In geodesic coordinates built from an orthonormal basis, . Every radial curve has coordinates , and substitution into the geodesic equation givesTaking proves .
Conversely, assume the metric and Christoffel-symbol conditions. For every in the star domain, satisfies the geodesic equation and has initial velocity in an orthonormal coordinate frame. Uniqueness of solutions to ordinary differential equations gives wherever defined. The star-domain assumption covers all of , so is precisely a geodesic coordinate chart. This is the Radial Christoffel-symbol criterion for geodesic coordinates.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 309 1 a ii Solution Created 2026-09-24 Updated 2026-09-25
Write and . Varying with fixed endpoints and then choosing proper time as parameter, for which , gives the Euler-Lagrange equationExpanding the derivative, raising the free index with the inverse metric, and using the symmetry of gives the geodesic equationThese are the Christoffel symbols of the Levi-Civita connection.
Past exam of the mathematics course of the University of Cambridge 2025 ib Paper 1 2F Solution Created 2026-09-23 Updated 2026-09-25
In local coordinates with metric , the energy isThe Euler–Lagrange equations are equivalentlywhere .
For the plane-section curve , constant speed gives . Both and the surface normal lie in , while is spanned by and that normal along the intersection. Hence is normal to the surface. Its tangential acceleration vanishes, which is the geodesic equation.
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 312 4 ii Solution Created 2026-09-24 Updated 2026-10-03
Divide the time component of the geodesic equation by and use . To first order, . Substitution of the supplied Christoffel symbols makes the background terms cancel the derivative of . The derivatives of the lapse and shift also combine, leavingThus the comoving photon energy is conserved in the unperturbed spacetime and changes through the gradient of the scalar gravitational source.
Past exam of the mathematics course of the University of Cambridge 2025 ii Paper 3 25I b ii Solution Created 2026-09-24 Updated 2026-09-25
A unit-speed surface curve is a geodesic when its acceleration is normal to the surface, equivalently when its covariant acceleration vanishes. In coordinates , the Christoffel symbols of the Levi-Civita connection areThe coordinate functions of a geodesic satisfy the geodesic equation
Past exam of the mathematics course of the University of Cambridge 2025 ii Paper 4 37E b Solution Created 2026-09-24 Updated 2026-09-25
For a slowly moving particle in a static weak field, the spatial part of the geodesic equation reduces toTo first order in the perturbation,and henceNewtonian acceleration is , so . Substitution into part (a), followed by the Poisson equation , givesThus the Newtonian limit of general relativity fixes
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 309 1 a Solution Created 2026-09-24 Updated 2026-09-25
A Killing vector field obeys , or equivalently . Along an affinely parametrized geodesic with tangent ,The second term vanishes by the geodesic equation, while the first contracts the symmetric tensor with the antisymmetric part selected by the Killing equation. Thus is a geodesic conserved quantity from a Killing vector. In Minkowski spacetime, translational Killing fields give conserved energy-momentum and rotational or boost Killing fields give the corresponding angular-momentum and boost charges; the same construction works for any spacetime isometry.
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 311 1 a i Solution Created 2026-09-24 Updated 2026-09-25
Because is a null tangent, metric compatibility givesBecause is tangent to an affinely parametrized null geodesic congruence,by the geodesic equation. Thus has no component along in either index.
For a tensor cosmological perturbation , the time geodesic equation in a local orthonormal tetrad gives . The photon comoving energy removes the background redshift; the dot is a partial time derivative, whereas the energy derivative follows the ray.
For the metric in vector cosmological perturbation, an orthonormal tetrad is , to first order. A photon has and , so the covariant component is . The covariant geodesic equation gives . The derivative of the scale factor cancels by the null vector condition, proving the redshift formula.
For a connected Riemannian manifold, two-point homogeneity is equivalent to the isometry group being transitive on the unit tangent bundle. One direction follows by taking short equal-length radial geodesic segments: the Gauss lemma identifies their distance, and injectivity of the exponential map identifies the initial directions after the endpoints are matched. Conversely, unit tangent transitivity implies point homogeneity, hence completeness. The Hopf-Rinow theorem supplies minimizing geodesics for arbitrary equal-distance pairs. Matching their initial unit tangent vectors and using uniqueness of the geodesic equation matches their other endpoints.