Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 81 4 a Solution Created 2026-10-03 Updated 2026-10-07
Let . On a site, empty and doubly occupied states have spin zero, while either singly occupied state has spin . ThusThe on-site spin-square normal-ordering identity rewrites the interaction as . Its contact coefficient is in this parameterization, rather than the convention often used for the Hubbard model.
Using a fermionic coherent-state trace and time slicing, replace each normal-ordered monomial by its Grassmann field symbol. With ,The independent fields have antiperiodic thermal boundary conditions. Normal ordering is crucial: the explicit subtraction removes the spin-square contraction, so there is no extra chemical-potential shift from it.