Let , so that the total number of Ising spins is . Write and group each triangle's two base spins and its apex into one cell. The Ising chain with alternating triangular decorations has a triangle bond followed by an undecorated connecting bond. Summing an apex Ising spin first gives a decorated-bond Boltzmann weightThe undecorated bridge has Boltzmann weight . In the basis ,Each cell contributes , so periodic boundary conditions giveThe two matrices have common normalized eigenvectors and , expressing spin inversion symmetry. Their respective eigenvalues areConsequently the cell transfer matrix has eigenvaluesand the finite-size partition function isFor , and , so only survives in the thermodynamic limit. Divide the Helmholtz free energy by , the number of sites rather than the number of cells or base spins:As a counting check, gives , , hence , exactly the number of independent Ising spin configurations. This model has separated decorated bonds and should not be confused with the corner-sharing sawtooth Ising chain, which has a different site count.
For low temperature, factor out the largest Boltzmann factor from the dominant eigenvalue:Thus the Helmholtz free energy per site has the expansionDifferentiate at fixed , remembering that . The entropy per site isThe nonzero residual entropy comes from an exponentially large ground-state degeneracy, generated by geometrical frustration. A triangle with antiferromagnetic energy has minimum energy : if , the apex must have the opposite sign; if , either apex sign is permitted. The two all-equal configurations instead have energy . Thus exactly one of a minimum-energy triangle's bonds is frustrated. The bridge can simultaneously minimize its energy at by requiring , where is the next cell's first base spin.
For fixed and , the number of allowed apex choices is therefore two when and one when . The zero-temperature counting transfer matrix on successive first base spins isThe eigenvalues of are and . Dividing by the sites and taking the thermodynamic limit gives , independently confirming the derivative calculation. This does not assert a unique ordered ground state: the extensive choice of frustrated bonds is precisely what leaves entropy at zero temperature. At high temperature, all Ising spins become independent and per site.
Let , so that the total number of Ising spins is . Write and group each triangle's two base spins and its apex into one cell. The Ising chain with alternating triangular decorations has a triangle bond followed by an undecorated connecting bond. Summing an apex Ising spin first gives a decorated-bond Boltzmann weightThe undecorated bridge has Boltzmann weight . In the basis ,Each cell contributes , so periodic boundary conditions giveThe two matrices have common normalized eigenvectors and , expressing spin inversion symmetry. Their respective eigenvalues areConsequently the cell transfer matrix has eigenvaluesand the finite-size partition function isFor , and , so only survives in the thermodynamic limit. Divide the Helmholtz free energy by , the number of sites rather than the number of cells or base spins:As a counting check, gives , , hence , exactly the number of independent Ising spin configurations. This model has separated decorated bonds and should not be confused with the corner-sharing sawtooth Ising chain, which has a different site count.
