Equal product masses imply equal kinetic energies and opposite momenta in the center of mass frame. The laboratory frame has nonzero initial momentum because the proton is moving. Conservation of momentum therefore forbids the two laboratory momenta from always being equal and opposite. The products are equal in laboratory kinetic energy only for particular emission directions, not for every event.
An exact two-body calculation makes this distinction quantitative. Write , , , and for incident kinetic energy. Express every quantity below in the same energy units; is momentum times the speed of light. For a stationary target,Here is the center-of-mass energy, and is the center-of-mass speed divided by the speed of light. Each outgoing alpha particle has center-of-mass total energy and momentum-times- magnitude . A Lorentz transformation gives the paired laboratory kinetic energies, with measured from the incident beam in the center of mass frame:Their sum is independent of and equals . Their difference is ; the symmetry belongs to the product interchange and the center of mass frame.
For the chosen model, subtract electron rest masses from each neutral-atom mass, neglect electronic binding energies, and use .[ref]
CODATA recommended values of the fundamental physical constants: 2022 by National Institute of Standards and Technology. CODATA 2022 wall chart, electron mass, energy equivalent in MeV
At , the paired laboratory kinetic energies are approximately and ; at both are approximately . In the latter case both products have a forward laboratory momentum component, so even equal laboratory kinetic energies do not imply back-to-back laboratory trajectories. A real thick target and finite detector acceptance would broaden or select these ideal kinematic possibilities. Articles by others on the same topic
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