Taking the Laplace transform, using linearity and the preceding three formulas, gives
Since , division by gives for in the domain of convergence. There is no genuine singularity at : continuity of the Laplace transform there supplies the same value. One can also first work with , where division is harmless.
The formula in part (iii) identifies as the Laplace transform of . By uniqueness of the Laplace transform,
As a direct check, and . Any two solutions of this initial value problem differ by and have the same initial value, forcing . This also verifies uniqueness independently of transform inversion.

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