Past exam of the biological physics course of the University of Oxford / 2021 / 5 / b / Solution

Use the supplied $-50\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$ as a standard transformed Gibbs free energy of ATP hydrolysis, rather than replacing it with a different commonly quoted standard value. Approximate thermodynamic activities by concentrations divided by $c^{\circ }=1\mathrm{M}$, at an explicitly assumed $T=300\mathrm{K}$. The dimensionless reaction quotient isConsequentlyand the reverse synthesis cost is $g_{\mathrm{ATP}}=63.22\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$. Substituting bare millimolar numbers in this quotient without the standard state would give the wrong logarithm.

For outside-to-inside proton movement, the membrane potential is $\Delta \psi =-0.125\mathrm{V}$ and ${\mathrm{pH}}_{\mathrm{in}}-{\mathrm{pH}}_{\mathrm{out}}=0.5$, so $[H^{+}{]}_{\mathrm{in}}/[H^{+}{]}_{\mathrm{out}}=10^{-0.5}$. The molar electrochemical potential change isThus the available proton-motive force magnitude is $0.15476\mathrm{V}$, supplying $14.93\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$ per transported proton. Assuming one proton per c-subunit per revolution, three ATP per revolution and no leakage, slippage or transport overhead,The smallest integer permitting synthesis is therefore $\boxed{n_c=13}$ in this ideal budget. A ring of thirteen gives only a small driving margin; inefficiency or sustained finite output could require a larger ring. The result is an energetic lower bound and near-reversible estimate, not a unique structural determination from these data. Reasonable temperatures near $300$–$310\mathrm{K}$ leave the minimum integer thirteen. Additional membrane transport costs have been excluded explicitly.