Differentiate the defining relation at . The linear term gives the Lie algebra
Solving this equation between matrices yields
where a convenient basis is
The first two generate Lorentz boosts and the last a spatial rotation. Direct commutators give
There are three independent real coefficients, so . A Cartan subalgebra is , and the rank of a semisimple Lie algebra is one. Explicitly, if and , their commutator vanishes exactly when
For nonzero , these equations force to be proportional to , so there is no two-dimensional commuting subalgebra. The split real rank is also one, realized by the semisimple Lorentz boost generator . Thus
For this Lorentz algebra in three spacetime dimensions, disconnected components of the full Lorentz group do not change its tangent Lie algebra at the identity.

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