Write , where each is a labelled copy of the topological space , with its topological disjoint union topology. Define the bijection
For a subset , let . By definition of the topological disjoint union, is open in exactly when each is open in .
The same condition characterizes open sets in the product topology on . If is open, the map is continuous, so each is open. Conversely, if each is open, then
is open, since the discrete topology makes every open in . Hence and its inverse function are continuous, proving the required homeomorphism. This also covers the case .

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