Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 336 3 Solution Created 2026-10-03 Updated 2026-10-06
Use the geometrical optics conventionBecause and , differentiating gives an order-one physical angular frequency and order-one physical wavenumbers. Absorb a constant leading amplitude phase into and take real; for a complex amplitude the corresponding quadratic density is .
Substitution into the wave equation gives the eikonal equation for a variable-speed wave at leading order:Choose the positive-frequency branch , ; the negative branch can be treated in exactly the same way. The imaginary first-order terms giveMultiplying by puts this wave-action transport for a variable-speed wave in conservation form:Its density is and its flux is that density times the group velocity. Independently, equality of mixed wave phase derivatives givesThis phase compatibility in geometrical optics is essential when converting the differentiated dispersion relation into equations along rays.
For completeness let be a general local dispersion relation. Define ray tracing by . Using the chain rule in and the symmetry givesLikewise cancels its advective term because . Hence the Hamiltonian ray equations for a local dispersion relation areThe derivatives on the right hold the wavevector fixed. For this wave equation they reduce to
When , the ray invariants are and , while . For a monochromatic component with these fixed invariants write , soUsing the stated independence of from , the wave-action transport for a variable-speed wave becomes . ThereforeThis is the stationary wave amplitude in a stratified wavespeed; is the constant for that component or ray family.
At the proposed simple turning point of a variable-speed wave, take and . On the chosen positive branch this entails . DefineAs the ray approaches from below, andThe amplitude diverges and the vertical group velocity vanishes. The WKB approximation also fails its slow-variation condition when . The turning-point enhancement of wave amplitude shows that this divergence is a failure of the outer ray approximation, rather than an actual infinite solution.
To derive the inner wavefield directly, separate the conserved horizontal wave phase and frequency in the original differential equation:Dividing by gives . Set . The second derivative is of size , whereas , so the Airy scaling at a variable-speed wave turning point isThe first-derivative term is smaller by , and higher coefficients in the expansion of give the same relative order. Thus the general leading inner profile is a linear combination of the two Airy functions and . For decaying Airy continuation and ray reflection, if the physical continuation is bounded and decays into , its growing coefficient is zero. In that usual evanescent continuation the wavefield has the formWithout a condition in the evanescent region the corresponding term remains admissible locally; the given existence of a wavefield below the turning point alone does not select its coefficient.
Finally, the outer amplitude at distance is for and fixed nonzero . The oscillatory Airy turning-point connection formula has exactly the same envelope on the allowed side. Therefore the inner wavefield has magnitude . The decaying Airy continuation matches an incident and reflected pair of rays, so a single upward branch must be supplemented by its reflected branch near the turning point; no formal coefficient matching is needed to identify this magnitude.