For a measure-preserving transformation and , the ergodic averages
converge almost everywhere to , the conditional expectation on the invariant sigma-algebra. The limit has the same integral as .
In a probability measure-preserving system whose transformation is an ergodic transformation, a nonnegative measurable with has almost everywhere. Apply the pointwise ergodic theorem to on a common full-measure set for integer , then bound the lower limit by each truncated integral. The monotone convergence theorem sends those integrals to infinity. The finite-integral case is the ordinary pointwise ergodic theorem.
For a measure-preserving transformation and real integrable , let . For the lemma asserts . Passing to the increasing union gives the corresponding infinite-supremum inequality.
Suppose almost everywhere and in a probability measure-preserving system. Then
almost everywhere and in , where is the invariant sigma-algebra. For the almost-everywhere assertion, bound the terms with index at least by , apply the Birkhoff ergodic theorem, and then let . The finitely many remaining end terms vanish by the linear growth bound for integrable observables.
In a probability measure-preserving system, implies almost everywhere. For every , the tail integral formula for moments gives . Invariance and the Borel-Cantelli lemma finish the proof. Consequently division by also gives zero for every .
For every , choose . On the Bernoulli shift over independent uniform coordinates in , the observable is integrable, but . The events are independent and their probabilities have divergent sum, so the Borel-Cantelli lemma implies that infinitely often almost surely. No exponent below one gives a universal bound for all integrable observables.
On a finite measure space, the convergence in the Birkhoff ergodic theorem also holds in . Prove it first for bounded truncations by the dominated convergence theorem, then use the contraction and Fatou lemma to remove the truncation.

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