One of the four following states:

When unqualified as in "the Bell state", it generally just means $|{\Phi }^{+}⟩$.

The Bell states are entangled and non-separable. Intuitively, we can see that when we measure that state, the values of the first and second bit are strictly correlated. This is the hallmark of quantum computation: making up states where qubits are highly correlated to match a specific algorithmic answer, and opposed to uniformly random noise. For example, the Bell state circuit is a common hello world, e.g. it is used in the official Qiskit hello world.

Once Ciro was at a University course practical session, and a graduate was around helping out. Ciro asked if what the graduate did anything specifically related to the course, and they replied they didn't. And they added that:Even though Ciro was already completely disillusioned by then, that still made an impression on him. Something is really wrong with this shit.

Other people that think that the educational system is currently bullshit as of 2020:

An upstream repo at: github.com/raspberrypi/pico-micropython-examples

Our examples at: rpi-pico-w/upython.

The examples can be run as described at Program Raspberry Pi Pico W with MicroPython.

There is no userland process for it, it is handled directly by the Linux kernel: unix.stackexchange.com/questions/439801/what-linux-process-is-responsible-for-responding-to-pings/768739#768739

20k genes, 3 billion base pairs. We can handle this!!!

A young Ciro Santilli really liked this game, the way it makes you feel.

Given a matrix $A$ with metric signature containing $m$ positive and $n$ negative entries, the indefinite orthogonal group is the set of all matrices that preserve the associated bilinear form, i.e.:Note that if $A=I$, we just have the standard dot product, and that subcase corresponds to the following definition of the orthogonal group: Section "The orthogonal group is the group of all matrices that preserve the dot product".

As shown at all indefinite orthogonal groups of matrices of equal metric signature are isomorphic, due to the Sylvester's law of inertia, only the metric signature of $A$ matters. E.g., if we take two different matrices with the same metric signature such as:and:both produce isomorphic spaces. So it is customary to just always pick the matrix with only +1 and -1 as entries.

Ciro Santilli feels a bit like this guy:

One big divergence: obsession with translating every page into every language.

His Mathematics Genealogy Project entry: www.genealogy.math.ndsu.nodak.edu/id.php?id=56185

Old French website: spoirier.lautre.net/

singlesunion.org/ so cute, he's looking for true love!!! This is something Ciro often thinks about: why it is so difficult to find love without looking people in the eye. The same applies to jobs to some extent. He has an Incel wiki page: incels.wiki/w/Sylvain_Poirier :-)