A single exponential map is not enough to recover a simple Lie group from its algebra Updated 2025-06-17 +Created 1970-01-01
TODO evaluate. No
pip install
???Behavior fully described by quantum electrodynamics.
Related:
- twitter.com/yoheinakajima/status/1759107727463518702 "smallest RAG test possible of an indirect relationship on a knowledge graph"
- www.quora.com/Do-knowledge-graphs-bases-have-a-place-in-the-pursuit-of-artificial-general-intelligence-AGI-or-can-their-features-be-better-represented-in-a-learning-based-system "Do knowledge graphs / bases have a place in the pursuit of artificial general intelligence (AGI), or can their features be better represented in a learning-based system?"
What you would see the moving rod look like on a photo of a length contraction experiment, as opposed as using two locally measured separate spacetime events to measure its length.
Given the function :the operator can be written in Planck units as:often written without function arguments as:Note how this looks just like the Laplacian in Einstein notation, since the d'Alembert operator is just a generalization of the laplace operator to Minkowski space.
Some sources say that this is just the part that says that the norm of a function is the same as the norm of its Fourier transform.
The comment at math.stackexchange.com/questions/446870/bijectiveness-injectiveness-and-surjectiveness-of-fourier-transformation-define/1235725#1235725 may be of interest, it says that the bijection statement is an easy consequence from the norm one, thus the confusion.
TODO does it require it to be in as well? Wikipedia en.wikipedia.org/w/index.php?title=Plancherel_theorem&oldid=987110841 says yes, but courses.maths.ox.ac.uk/node/view_material/53981 does not mention it.
There are unlisted articles, also show them or only show them.