Angular momentum of a radial function times a linear polynomial Created 2026-10-05 Updated 2026-11-05
Orbital angular momentum operators annihilate a radial multiplier . Their squared sum sends every degree-one homogeneous polynomial to times that polynomial, so a nonzero normalizable state has angular momentum quantum number . With real and real coefficients, its third-component expected value is zero by angular symmetry, though it need not be an eigenstate of that component.
Past exam of the chemistry A course of the University of Cambridge 2021 Paper 1 A3 b iii Solution 2026-10-20
The calculated rotational constant gives . At room temperature, taken as , the continuous maximum is ; comparing the adjacent integer populations gives . Taking instead gives and the same integer answer.
Past exam of the condensed matter physics course of the University of Oxford 2022 4 d i Solution 2026-10-25
The given electron configuration has an inert closed core and two electrons. The Aufbau principle identifies the occupied subshells; the free-ion term within the open configuration is then selected by Hund's rules. A closed core contributes .
Each electron has orbital angular momentum quantum number . Place the two spins parallel, so . The Pauli exclusion principle then requires distinct orbital projections. The largest allowed total projection is , obtained from and , giving the maximum allowed . A larger would place two parallel-spin electrons in the same atomic orbital and is forbidden.
The subshell holds fourteen electrons; is less than half filled. The third of Hund's rules therefore selects . HenceThe term symbol uses and the spectroscopic letter for . The praseodymium ion retains an orbital contribution, so a spin-only estimate would be inappropriate.
The angular momentum eigenstates have eigenvalue , where the angular momentum quantum number is . For each , the magnetic quantum number runs in unit steps from to . Here that magnetic quantum number is , so only half-integer are compatible:Integer cannot contain a eigenvalue . Applying the angular momentum lowering operator and using givesThe lowered vector is nonzero, since the adjoint operator identity givesFinally, is a self-adjoint operator, so its eigenstates for distinct eigenvalues are orthogonal. Explicitly,and hence .
The angular momentum commutation relations arewhere is the Levi-Civita symbol. The angular momentum eigenstates havewith angular momentum quantum number and magnetic quantum number . There are such states in one irreducible spin representation, so the eigenspace has dimension within that multiplet. The use of avoids confusing the magnetic quantum number with the particle mass in the earlier questions.
For completeness, the ladder operators satisfy andThe upper and lower ends are ; integer steps between them require to be a nonnegative integer. This explains both the spectrum and the multiplet dimension. Pure orbital angular momentum permits only integer , whereas general spin allows half-integers. If a larger Hilbert space contains several copies of the same irreducible spin representation, the full eigenspace includes all those copies: its dimension is times their multiplicity, and can be infinite. The paper's dimension question is understood per irreducible multiplet.
Rotational energy 2026-10-20
For a linear rigid rotor with moment of inertia , the energy eigenvalue at angular momentum quantum number is . Each level has statistical weight before additional symmetry or nuclear-spin restrictions.