Past exam of the mathematics course of the University of Cambridge 2005 ii Paper 2 3G Solution Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2016 ib Paper 1 3F d Solution Created 2026-09-24 Updated 2026-10-06
Use an isometry of the Poincare disc model to move the centre to zero. A hyperbolic disc of radius then has Euclidean radius by the hyperbolic distance formula. The area element of a surface of the Riemannian metric is , soTherefore the area is independent of the centre, and
Past exam of the mathematics course of the University of Cambridge 2016 ib Paper 4 15F b Solution Created 2026-09-24 Updated 2026-10-06
The generating circle has , and its revolution is a torus. From part (a), and the area element of a surface is . ThereforeThe positive Gaussian curvature on the outer side exactly cancels the negative curvature on the inner side. Equivalently, the Gauss-Bonnet theorem gives because the Euler characteristic of the torus is zero.
Past exam of the mathematics course of the University of Cambridge 2020 ii Paper 3 25I c Solution Created 2026-09-24 Updated 2026-10-03
Put . The Jacobi equation in geodesic polar coordinates and the initial conditions from part (b) areInside a geodesic polar coordinate ball, . If , then , so and therefore . The Riemannian area element is , whenceThus nonpositive Gaussian curvature makes such a ball at least as large as the Euclidean disk of the same radius.
Past exam of the mathematics course of the University of Cambridge 2023 ii Paper 4 25G a Solution Created 2026-09-24 Updated 2026-09-25
For a positively oriented local parametrization with first fundamental formthe area element of a surface isUnder an orientation-preserving coordinate change, the Jacobian from cancels the inverse Jacobian in the square root of the metric determinant. Hence these local expressions agree and define a global two-form.
The Euler characteristic may be defined from any finite triangulation byor equivalently by the alternating sum of the dimensions of the rational homology groups. Subdivision leaves unchanged, and the homological formula shows that it is a topological invariant, so the definition does not depend on the triangulation.
Give the boundary its induced orientation and parametrize it by arc length. If is its unit tangent and is the chosen unit normal to the surface, its signed geodesic curvature iswhere is the surface covariant derivative. The Gauss-Bonnet theorem for a compact oriented surface with smooth boundary and no corners iswhere is the Gaussian curvature.