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Carl Friedrich von Weizsäcker developed a semi-empirical description of nuclear masses and mass defects. The semi-empirical mass formula connects nuclear binding energy with the number and arrangement of protons and neutrons, rather than treating every measured mass as an unrelated datum. In modern explanatory terms, bulk binding scales roughly with the nucleon number $A$, a surface correction with $A^{2/3}$, and the electrostatic cost with $Z^2/A^{1/3}$. These competing scalings explain why increasing nuclear size does not improve the binding per nucleon indefinitely.^[ref]

A physicist.^[ref][ref]

For electrically neutral, fully ionized stellar matter with electrons and Positrons as its charged leptons, the electron fraction in stellar matter is the net electron number per baryon:Here $n_i$ is the number density of nuclear species $i$, $Z_i$ its atomic number, $A_i$ its mass number, and $n_b$ the total baryon number density. Charge neutrality equates the net negative lepton charge to the total proton charge. The subtraction of Positrons matters in hot matter containing abundant thermally produced Positrons; ordinary electron number alone need not equal nuclear charge.^[ref]

Neglecting small nuclear mass defect corrections, isotope mass fractions $X_i$ give $Y_e={\sum }_i{X}_i{Z}_i/A_i$. Pure fully ionized helium-4 therefore has $Y_e=1/2$. Strong interactions and electromagnetic reactions preserve this proton fraction, whereas electron capture and beta-plus decay reduce it and beta-minus decay can increase it. The total proton-to-neutron number ratio is $Y_e/(1-Y_e)$; electron-positron pair production changes neither of those baryon counts. If other charged leptons such as muons are appreciably populated, their charge must also be included in the neutrality equation.

Nuclear physics studies atomic nuclei, their internal structure and the processes that change them. A nucleus contains protons and neutrons, whose short-range nuclear forces bind them while the Coulomb force repels the protons. The resulting nuclear energy levels and nuclear binding energies connect this subject to the low-energy consequences of quantum chromodynamics. Weak interactions additionally permit changes of nuclear composition through beta decay.

The mass defect makes the connection between structure and released energy quantitative. For a nucleus with $Z$ protons, $N$ neutrons and nuclear mass $M_{\mathrm{nuc}}$, its nuclear binding energy isA bound nucleus has less rest energy than its separated nucleons. In a nuclear reaction, the difference between the sums of initial and final rest energies supplies the Q value. The sign of that difference and the Coulomb barrier answer different questions: a reaction can release energy overall while still requiring a way to cross an entrance barrier.

Scattering experiments supplied an early structural clue. Rare large deflections of alpha particles by thin matter could be explained by close encounters with a highly concentrated central charge. Ernest Rutherford's 1911 analysis connected such angular measurements to a compact atomic centre, establishing a route from measured scattering cross-sections to internal structure.^[ref]

The stipulated decay branch gives $K_{\alpha }\simeq 4.51\mathrm{MeV}$. Using the supplied atomic masses, the mass defect isso the total Q value is $Q\simeq 0.00580(931.494)=5.4027\mathrm{MeV}$. The photon carries away the stated $0.802\mathrm{MeV}$, leavingApplying the recoil partition,The daughter recoil takes approximately $0.0877\mathrm{MeV}$. Atomic electron counts balance in the neutral-atom mass difference; small electronic binding corrections and photon recoil are neglected consistently with the problem. These values follow the branch specified in the examination, rather than an assumed average over every physical decay branch.

Denote the parent rest mass by $M$, the daughter rest masses by $m_i$, and their total energies in any inertial frame by $E_{\mathrm{before}}$ and $E_{\mathrm{after}}$. For an isolated disintegration with all products included, energy conservation gives $E_{\mathrm{after}}=E_{\mathrm{before}}$. The corresponding kinetic energies are $K_{\mathrm{before}}=E_{\mathrm{before}}-M{c}^2$ and $K_{\mathrm{after}}=E_{\mathrm{after}}-{\sum }_i{m}_i{c}^2$. ConsequentlyEvery mass on the right is a rest mass, hence invariant under a Lorentz transformation. This proves the kinetic energy released by relativistic decay is frame independent even though either total kinetic energy separately is not. In the parent rest frame the initial kinetic energy vanishes and the final kinetic energy equals the energy associated with this mass defect. External energy input or omission of radiation would invalidate the energy-cancellation step; if photons are products, include their energies with zero rest-mass subtraction.

Use the supplied atomic masses consistently. Their mass defect per four hydrogen atoms is $4(1.0078)-4.0026=0.0286$ atomic mass units. The conversion efficiency isThe atomic-mass bookkeeping includes the associated positron-annihilation energy; an exact photon-heating budget also subtracts energy carried away by neutrinos. With the stated ten-percent fuel fraction and constant present solar luminosity, the main sequence lifetime estimate isThe much longer timescale explains why stellar nuclear fusion can power the Sun throughout its long main-sequence history.