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At a positive interior maximum, $u_x=0$, $u_{xx}\le 0$, and $u_t\ge 0$ if the point is compared with its past. The PDE instead gives $u_t\le -u^3<0$, a contradiction. Thus a positive global/past-strip maximum must come from the spatial boundary or initial-time limit. The far value is positive, so any attained global maximum is positive; the argument does not prohibit a negative local maximum in isolation.

For uniqueness put $w=u_1-u_2$. It satisfiesThe parabolic comparison principle with zero difference data gives $w\le 0$ and then $-w\le 0$, hence $w=0$. As usual on this noncompact singular-time domain, this uses an admissible comparison class in which the initial and far-field limits justify truncation; for example bounded/subquadratic differences on finite past strips with the corresponding uniform zero traces suffice. A barrier $\delta (1+x^2+2t)$ controls spatial infinity, since ${\partial }_t-{\partial }_x^2+[x/(2t)]{\partial }_x+a$ applied to it is nonnegative. The printed fixed-point limits alone should not silently be substituted for all uniform/growth hypotheses of this comparison argument.

Use drift cancellation in a parabolic similarity reduction. For the similarity ansatz, derivative scaling givesThus $\boxed{\beta =1/2}$, the drift terms cancel, and $f^{\prime \prime }=f^3-f/2$ with $f(\infty )=1/\sqrt{2}$. Use the positive-equilibrium separatrix for a cubic profile equation. Multiply by $f^{\prime }$ and use the limiting equilibrium to determine the integration constant:The branch approaching the positive far equilibrium satisfies $f^{\prime }=(1/2-f^2)/\sqrt{2}$; the constant equilibrium is included as well. Separation givesFor a finite boundary value at $x=0$ and no interior pole, take $A>-1$. Values $-1<A<0$ describe the corresponding coth-type approach from above; $A=0$ is constant, and positive $A$ gives the tanh-type branch. The other first-integral sign cannot approach the positive equilibrium nontrivially as $\eta \to \infty$.

The requested deficit integral is, after $x=\sqrt{t}\eta$,Therefore $\boxed{A=1}$, and the selected solution is $\boxed{u(x,t)=(2t{)}^{-1/2}\tanh [x/(2\sqrt{t})]}$.

Use the usual fractional Dirichlet domain scale: $A=-{\Delta }_D$ on $H=L^2(\Omega )$, and $H_{\rho }=D(A^{\rho })$. Its Sobolev embedding theorem givesSuch a positive $\beta$ exists precisely because the assumed $\delta$ is greater than $n/4$. Consequently $v=u_t$ is continuous in time with values in this Hölder space on every compact positive-time interval. This embedding alone gives no two spatial derivatives for $v$; those must come from the equation.

First establish a bound that will also justify the nonlinear regularity steps. Put $F(s)=\lambda s-s^3$ andThe constants $K$ and $-K$ enclose both the initial data and the zero Dirichlet boundary data. Moreover $F(K)\le 0$ and $F(-K)\ge 0$, so they are a supersolution and a subsolution for the parabolic comparison principle. A direct energy proof avoids assuming pointwise continuity at time zero. Let $h=(u-K{)}_{+}$. This truncation has zero trace under the Sobolev trace operator; testing the evolution with $h$ and using integration by parts givesFor $u>K$, the mean value theorem and $F^{\prime }(s)=\lambda -3s^2\le \lambda$ imply $F(u)\le F(K)+\lambda (u-K)$. ThereforeThe Gronwall inequality gives $h=0$, since its initial L2 norm vanishes. For the initially rough datum, apply the inequality from $\epsilon >0$ and let $\epsilon \downarrow 0$, using $u(\epsilon )\to u_0$ in L2 space. The same argument for $-u$, which satisfies the same equation because $F$ is odd, provesThis is the invariant interval for a cubic reaction-diffusion equation; the energy calculation is valid by the Sobolev chain rule and approximation even before the stronger pointwise regularity is established.

Now fix $0<\tau <t_0$ and, if necessary, reduce the positive Hölder exponent $\beta$. Rearranging the evolution gives the elliptic identityIts right side is bounded on $[\tau ,t_0]\times \Omega$, because $v\in C([\tau ,t_0],C^{0,\beta })$ and $|u|\le K$. Boundary elliptic regularity first gives $u(t)\in W^{2,p}(\Omega )$ for every finite $p$, uniformly on this time interval. For $p>n$, the Sobolev embedding theorem makes $u(t)$ spatially continuously differentiable, with a positive Hölder exponent. Thus $F(u(t))$ lies in $C^{0,\beta }$ after reducing $\beta$ if necessary. The global Schauder estimate then gives $u(t)\in C^{2,\beta }(\overline{\Omega })$.

These are continuous-in-time, not just separate-time, regularity statements. Since $v\in C(C^{0,\beta })$, the identity $u(t)-u(s)={\int }_s^{t}v(r)dr$, initially an identity in L2 space, holds in $C^{0,\beta }$ once $u(s)$ is known to belong to that space. Hence $u$ is locally Lipschitz in time into $C^{0,\beta }$. Apply the global Schauder estimate to the difference of the two elliptic identities. Continuity of $v$ and of $F(u)$ into $C^{0,\beta }$ proves $u\in C([\tau ,t_0],C^{2,\beta })$.

To gain the spatial regularity of the time derivative itself, take time difference quotients of the evolution. If $d_h(t)=[u(t+h)-u(t)]/h$, their equations arewhereThe coefficients have uniformly bounded spatial Hölder norms and temporal Hölder norms on compact positive-time cylinders: this follows from the spatial regularity just proved and the local time Lipschitz bound in $C^{0,\beta }$. Also $d_h={\int }_0^{1}v(t+sh)ds$ is uniformly bounded and tends to $v$ in $C^{0,\beta }$. Positive-time parabolic Schauder estimates, applied away from the lower time edge, give uniform $C^{1+\beta /2,2+\beta }$ bounds for $d_h$, with a slightly smaller exponent if needed. Passing to the limit proves that $v$ is continuous into $C^2(\overline{\Omega })$ and satisfiesThe Dirichlet boundary condition for $v$ follows also by differentiating the identically zero boundary value in $C^0$. Since $\tau$ was arbitrary, this proves the requested, genuinely stronger regularity:This is positive-time smoothing for a semilinear heat equation; it is the extra parabolic step for $v$, not just the Sobolev embedding theorem, that gives the $C^1$ topology asserted here.

Finally, a uniform bound excludes a finite maximal existence time for this semilinear partial differential equation. Restart at any positive time $s$, using the heat semigroup on the Banach space $X=\{g\in C(\overline{\Omega }):g{|}_{\partial \Omega }=0\}$ with the supremum norm. Its variation-of-constants formula isThe heat semigroup is a contraction semigroup on $X$. On the ball of radius $K+1$, $F$ is Lipschitz with constant at most $|\lambda |+3(K+1{)}^2$, and bounded by $|\lambda |(K+1)+(K+1{)}^3$. Choose a time length $\eta >0$ so that the integral is at most $1$ and its Lipschitz constant is less than $1$. The Banach fixed-point theorem then gives a local solution on $[s,s+\eta ]$, with $\eta$ independent of $s$, because $\Vert u(s){\Vert }_{\infty }\le K$. If a finite maximal time existed, choosing $s$ less than $\eta$ before it would extend the same solution past it, a contradiction. Uniqueness identifies this continuation with the original solution, and positive-time smoothing restores the classical solution on each extended interval. The solution is globally defined and remains between $-K$ and $K$.

An anti-dynamo theorem identifies a restriction that prevents a conducting fluid from regenerating its magnetic field against resistive losses. The hypotheses matter: throughout the following arguments take positive uniform magnetic diffusivity, smooth fields, no imposed magnetic source, and the stated isolated or energy-closed boundary conditions. An anti-dynamo theorem does not rule out transient magnetic amplification, winding of an imposed field, or an externally supplied magnetic flux. The resistive induction equation is the common starting point:

First consider Backus' necessary condition for dynamo action. For a conductor contained in a sphere of radius $a$, include the potential field in the insulating exterior when defining the total magnetic energy:For an incompressible flow, with boundary conditions eliminating the mechanical surface term, such as a no-slip boundary condition for the fluid, integration by parts giveswhere $e_{ij}=({\partial }_i{u}_j+{\partial }_j{u}_i)/2$ is the rate-of-strain tensor. Its antisymmetric part does no stretching, since $B_i{B}_j$ is symmetric. If $S$ bounds the largest eigenvalue of $e$ throughout the flow, the first term is at most $2S{E}_B$.

The magnetic free-decay spectral bound for the enclosing insulating sphere isThe exterior energy is essential to this variational estimate. Its constant comes from the slowest freely decaying dipolar poloidal mode: the spherical radial matching condition reduces to $j_0(\kappa a)=0$, whose first positive root is $\kappa a=\pi$. Expanding an admissible field in the orthogonal free-decay modes, or using their variational characterization, gives the bound. A smaller conductor can only increase the minimum dissipation quotient for the enclosing-sphere comparison. Combining the two estimates yieldsThusBelow this threshold the Gronwall inequality gives exponential energy decay. Above it the estimate merely permits growth; it does not prove that the geometry regenerates the field. A time-dependent version bounds the field-amplitude exponent by the time average of the maximum strain minus the diffusive rate.

The geometric obstruction in Cowling anti-dynamo theorem is different: an isolated exactly axisymmetric magnetic field cannot be self-maintained. To see the missing regeneration mechanism, write its poloidal magnetic field in terms of the poloidal magnetic flux function $\psi$:The poloidal part of the resistive induction equation becomesThere is no term containing $B_{\varphi }$ that creates new poloidal flux. Fix the gauge by setting $\psi =0$ on the regular symmetry axis, and match to a decaying exterior field with no imposed flux. At a positive interior maximum away from the axis, the advective term vanishes and the diffusive term is nonpositive. The parabolic comparison principle therefore prevents increase of the maximum; it likewise prevents decrease of a negative minimum. In the steady problem the strong maximum principle, regularity at the axis and decay outside exclude a nonzero maximum altogether. Matching to the insulating exterior does not create a maximum at the interface: the exterior flux is harmonic in the corresponding axisymmetric operator, and the two normal-derivative conditions exclude such an interface extremum. The same homogeneous scalar diffusion problem gives decay in time on a bounded conductor with no replenishing boundary data.

Once the poloidal field has decayed, let $b=B_{\varphi }/r$ and let ${\Omega }_f=u_{\varphi }/r$ denote the fluid's angular velocity. Its equation isDifferential rotation can make toroidal field from poloidal field, but it cannot close the reverse loop. When ${\mathbf{B}}_p=0$, this too is a homogeneous advection-diffusion equation, with a regular axis and zero toroidal field at an insulating exterior. Hence it cannot sustain the remaining field. The exactly axisymmetric field, rather than merely an axisymmetric velocity, is excluded. If an exactly axisymmetric field were maintained by a nonaxisymmetric velocity, averaging the linear induction equation in azimuth would replace that velocity by its azimuthal mean and give the same contradiction. An axisymmetric flow can, however, excite a nonaxisymmetric field. Also an axisymmetric averaged field in mean-field dynamo theory has an additional fluctuating electromotive force, so this unmodified scalar proof does not apply to it.

The toroidal-velocity anti-dynamo theorem restricts the flow instead. In a conducting sphere, suppose $\mathbf{u}\cdot \mathbf{x}=0$, so the incompressible flow is tangent to every concentric sphere. No assumption of axisymmetry is made. Define $P=\mathbf{x}\cdot \mathbf{B}$. A direct Cartesian calculation is particularly useful:The last equality uses $\nabla \cdot \mathbf{B}=0$, so ${\nabla }^2(\mathbf{x}\cdot \mathbf{B})=\mathbf{x}\cdot {\nabla }^2\mathbf{B}$. Thus the radial magnetic scalar is a passive diffusing scalar, not a regenerated field. Multiplying by $P$, integrating over the sphere and using tangential incompressible advection givesIn an insulating exterior, a spherical harmonic component of degree $l\ge 1$ has $P\propto r^{-l-1}$, so its boundary contribution is negative: ${\partial }_{n}P=-(l+1)P/a$. The monopole component is absent because the magnetic field is solenoidal and regular. The resulting dissipative scalar problem makes $P$, and hence the poloidal field, decay.

When that radial field is absent, the remaining tangential solenoidal field can be written $\mathbf{B}=\nabla \times (T\mathbf{x})$. Its induction equation reduces to a second passive scalar equation. Indeedand the curl of the last gradient term is zero. Therefore $T_t+\mathbf{u}\cdot \nabla T=\eta {\nabla }^{2}T$, up to an irrelevant radial gauge function, which can be removed by taking the angular mean of $T$ to be zero. Its angular variations vanish at the insulating spherical boundary, so this scalar also decays by its quadratic energy identity. Equivalently, a putative growing magnetic normal mode must first have $P=0$, after which the scalar $T$ equation rules it out. Purely toroidal spherical flow cannot close a dynamo regeneration loop, even if it is nonaxisymmetric. This does not assert that purely poloidal flow is always incapable of a dynamo, or that any azimuthally directed cylindrical flow is governed by the same spherical theorem.

Other restrictions illuminate the same distinction between stretching and regeneration. The planar anti-dynamo theorem has a similar scalar proof in the usual two-dimensional geometry. For planar velocity and magnetic field independent of the third coordinate, write the in-plane field as $\nabla \times (A\hat{\mathbf{z}})$. Its vector potential obeys $A_t+\mathbf{u}\cdot \nabla A=\eta \Delta A$ after fixing the gauge, so $\frac{1}{2}\frac{d}{dt}\int A^2=-\eta \int |\nabla A{|}^2$ under periodic or homogeneous energy-closed boundary conditions. A third field component independent of that coordinate is also a passive scalar. A spatially uniform imposed field may survive in a periodic box but is not regenerated dynamo field. Three-component motions depending on only two coordinates are not covered by this strictly planar formulation.

There are also necessary bounds in terms of velocity amplitude rather than strain. The magnetic work term is bounded by $\Vert \mathbf{u}{\Vert }_{\infty }\Vert \mathbf{B}{\Vert }_2\Vert \nabla \times \mathbf{B}{\Vert }_2$; combining this with the same free-decay inequality gives a velocity-based lower threshold on the magnetic Reynolds number. These bounds, like Backus' necessary condition for dynamo action, are necessary rather than sufficient. Pure motion that only rearranges a scalar magnetic potential cannot evade diffusion merely by becoming faster. Conversely the stagnation-flow energy amplification in Question 2 does not contradict the bounded-body theorems: it uses an unbounded three-dimensional strain field and, for its growing finite-energy modes, a slowly decaying field at infinity. Similarly, the torsional Alfvén waves in Question 3 transfer energy between velocity and a toroidal perturbation about a prescribed background; they are not a construction of that background by dynamo action. The anti-dynamo results identify failed regeneration mechanisms and the assumptions under which those failures are rigorous.

Let $m_0={\min }_{x}u(x,0)>0$, which exists by periodicity and continuity. Fix any finite interval $[0,T]$ on which the classical solution is smooth. Choose $ϵ>0$ with $ϵ(1+T)<m_0/2$ and consider the strictly positive decreasing barrier $b(t)=m_0-ϵ(1+t)$.

Initially $u>b$. If this strict inequality first failed, compactness of the spatial circle would give a first contact $(x_{\ast },t_{\ast })$ with $u=b>0$. At that contact, the spatial minimum of $u-b$ has $u_x=0$, $u_{xx}\ge 0$, and the first-contact condition gives $(u-b{)}_t\le 0$. But the equation yieldsa contradiction. Therefore $u>b$ throughout the interval. Letting $ϵ\downarrow 0$ gives $\boxed{u(x,t)\ge m_0>0}$ on $[0,T]$. Since $T$ was arbitrary, positivity persists for every time for which the assumed smooth solution exists. This argument is a parabolic comparison principle proved directly and does not assume uniform parabolicity before positivity has been established.

For a differential equation $L[u]=0$ with its comparison order fixed, a supersolution satisfies $L[w]\ge 0$. For example, if $L={\partial }_t-{\partial }_x^2+Q$ with $Q\ge 0$, a sufficiently regular $w$ satisfying $L[w]\ge 0$ and dominating the initial and boundary data lies above a solution by the parabolic comparison principle. An unbounded-domain barrier such as $w=\eta e^{3t}(1+x^2)$ can provide the missing boundary control at large distance. The sign convention belongs to the chosen differential operator and must be stated.