This is a rovibrational spectrum: the vibrational excitation is accompanied by quantized molecular rotation. The high-wavenumber R branch has , and the low-wavenumber P branch has . In the simplest common- approximation,
Consecutive lines within either branch are therefore separated by roughly , while the gap between P(1) and R(0) is roughly . There is no Q branch: for this diatomic parallel transition, the electric-dipole rotational selection rule allows , and the line strength vanishes.
The intensity envelope comes from rotational populations, approximately , together with the rotational line strengths. The paired peaks arise from the two chlorine isotopologues, and : their different reduced masses shift both rotational and vibrational spacings. The more abundant gives the stronger member. The changing spacing away from the band centre reflects and, at higher , centrifugal distortion; it is not evidence for additional vibrational fundamentals.
Use the two-body reduced mass, rather than the chlorine mass or hydrogen mass alone:
The bond force constant gives
The requested “frequency in cm−1” is a spectroscopic wavenumber; the ordinary frequency is the value in s−1 above. This calculation uses the question's force constant in the harmonic model, rather than replacing it with a tabulated spectroscopic constant.
Read the stronger members of the inset doublets at about , and . Their spacings are roughly –, so the common- estimate is
Using the harmonic wavenumber from the preceding calculation and labelling lines by the lower-state ,
These are graph-based estimates. Finite reading precision and different upper/lower rotational constants limit their accuracy to a few cm−1; extra decimal places would not be justified. The R1 result refers to , while R0 is the line nearest the high-wavenumber side of the band gap.

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