For azimuthally symmetric Rutherford scattering, integrate over the solid angle, . Substituting gives , so
The small lower cutoff dominates when and . Using , the leading total cross section is
A nonzero cutoff is essential: the unscreened forward cross section otherwise diverges.
Let . The supplied second moment gives the single-scatter root mean square angle
For independent scatters with uniform azimuth, the small angular-deflection vectors have zero mean. Their cross terms average to zero, so their variances add. After scatters,
This is the root mean square magnitude of the two-dimensional angular deflection. Its projection into one specified plane has a variance smaller by a factor of two, hence a root mean square smaller by .
For a thickness with number density of scattering centres, the mean count is . Using the total cross section in i and the variance addition in ii,
Thus
The stated assumptions make the prefactor independent of and approximately independent of . The lower-cutoff factors cancel except inside the slowly varying logarithm. Treating as a Poisson random variable rather than a fixed count gives the same result after replacing by its mean.
The magnetic bending angle is . For a momentum estimate based on this angle, propagation of uncertainty gives . Comparing the total Multiple Coulomb scattering angle with the bend therefore gives the commonly intended characteristic estimate
Its independence of is the key result for relativistic particles: the scattering angle and magnetic bend both scale as .
A precise standard deviation requires specifying how tracks are measured. If is obtained from independently measured entrance and exit directions and all the material lies between them, the bending-plane projected root mean square is . For that estimator the equality is
A three-point sagitta fit weights scatter positions differently again. The paper does not specify these measurement details, so it fixes the scaling and characteristic estimate, but not one universal geometric coefficient for all track fits.

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