Treat the lake as a large thermal reservoir at , and take the copper's heat capacity constant over the cooling interval from . Although the actual cooling is irreversible, entropy is a state function, so its change can be calculated along a hypothetical reversible path:The lake receives at constant temperature, givingTherefore, neglecting other changes,The positive total is the entropy generated by transferring heat across a finite temperature difference. The copper's entropy decreases, but the colder lake gains a greater amount.
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