For the stochastic differential equation , the diffusion generator on smooth functions is
One form of the Feynman-Kac formula is the following. Suppose the stochastic differential equation is well posed and nonexplosive, is bounded, the terminal data and source are bounded, and is a classical solution bounded on finite time intervals of
With the regularity needed for the Itô formula, the parabolic Feynman-Kac formula with a source states
Here means expectation for the diffusion process started at . Under hypotheses ensuring existence of a classical solution, this representation also identifies that solution uniquely in the stated bounded class. In the remaining parts, , so solves the terminal-value Kolmogorov backward equation . Complex terminal data are allowed by applying the real formula to their real part and imaginary part separately.
The diffusion generator is . By the Feynman-Kac formula, the required conditional characteristic function solves
Use separation of variables in the form . Since and , the temporal factor satisfies the ordinary differential equation
Thus , and
This is bounded in absolute value by one, so it lies in the uniqueness class of the Feynman-Kac formula. As an independent check, integrating the stochastic differential equation gives . The independent Brownian increments have the normal distribution with mean zero and variance , yielding exactly the same characteristic function. For , the conditional distribution is a point mass at , and the same boxed expression still applies.
Here the diffusion generator is . The Feynman-Kac formula gives
Try , where and . Substitution and collection of the coefficients of and the constant term give
The solutions of these ordinary differential equations, with the terminal conditions imposed, are
For , define the conditional variance
Then the required conditional characteristic function is
In particular, for this exponent is . The variance is nonnegative for either sign of , and its limit at is . Hence the solution is bounded in absolute value by one and the Feynman-Kac formula identifies it with the required expectation. The value gives one directly, including that case without dividing by .
For an independent check, the integrating factor and the Itô product rule give
The stochastic integral has a normal distribution because its integrand is deterministic; the Itô isometry gives its variance as . For this is the Ornstein-Uhlenbeck transition distribution. The formula also covers the unstable case , and degenerates to deterministic motion when .
For , set . The candidate invariant probability law of a Markov process is
To prove invariance rather than merely guess a limiting probability distribution, initialize independently of future Brownian increments. Integrating the conditional characteristic function from part (i) against this centered normal distribution gives
because . The uniqueness theorem for characteristic functions implies for every . This proves , as required. The time-homogeneous Markov property then also makes the process with this Ornstein-Uhlenbeck stationary initialization a strictly stationary process.

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