Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 47 6 Solution Created 2026-10-03 Updated 2026-10-14
Use the usual minor and major symmetries of the elastic stiffness tensor, positive density, and strong ellipticity in elasticity. For the plane elastic wave , substitution into momentum balance gives the acoustic tensor problemThe major symmetry makes a real symmetric matrix. Moreover for nonzero under strong ellipticity in elasticity. Hence its three eigenvalues are positive and the three positive wave speeds are real. Symmetry alone proves only reality of : an unstable isotropic tensor with negative shear modulus has negative transverse . The requested reality therefore uses stability as part of the physical elastic-solid assumption.
The elastic slowness surface consists of three sheets, with , satisfyingIt is centrosymmetric. Sheets can meet at degenerate polarizations; they need not be spherical or convex in an anisotropic solid. The group velocity is normal to the corresponding smooth sheet: for a sheet tangent , differentiation of gives . The coefficient vector is proportional to the group velocity, so its scalar product with every tangent vanishes.
Fix horizontal slowness and put . DefineThe symbol on a tensor index is an index, whereas is a horizontal slowness component. The vertical slowness equation is the vertical slowness sextic of an anisotropic solidThe leading coefficient is , so it is a degree-six polynomial with real coefficients. Nonreal roots occur in conjugate pairs, leaving between zero and six real roots counted with multiplicity. Generically the counts are ; a grazing repeated root can give an odd count of distinct real roots. Geometrically these are the intersections of a vertical line of fixed horizontal slowness with the three sheets.
All four generic counts are actually possible in a stable material. For example, take and orthotropic Voigt stiffnessesThe stiffness matrix is positive definite. For horizontal slowness , the three diagonal acoustic equations areThe choices give respectively six, four, two and zero real vertical roots.
For the general depth-dependent amplitude, substitution of the horizontal harmonic factor yieldsFor six simple roots , choose nonzero null vectors of the corresponding matrix. The complete solution isComplex vertical roots give evanescent waves. At defective repeated roots the usual polynomial-in-depth factors multiplying exponentials must be included, or the solution can be defined by a limiting procedure.
To classify the modes, take positive downwards and . The reduced traction for a mode isMechanical energy crosses a plane at rate . Averaging the real harmonic fields uses . With velocity amplitude and traction amplitude , the time-averaged vertical acoustic energy flux isFor a real propagating mode, write its physical wavevector as . Differentiate in . The derivatives of cancel by the eigenvalue equation, while . Thus its vertical group velocity and flux areThus the elastic mode classification by vertical energy flux is upgoing if , downgoing if . In anisotropy, the sign of vertical phase slowness alone need not classify energy propagation. For evanescent modes, select for decay into a downward half-space and for decay into an upward half-space. Away from grazing and degeneracy, continuation from zero horizontal slowness, with a small radiation damping if needed, separates three outgoing modes on each side. Superpose only the appropriate three to construct the most general upgoing or downgoing field; limiting modes handle exceptional cases.
For a free surface at with solid occupying , let be a unit-amplitude incident upgoing mode. The reflected field consists of the three downgoing propagating or depth-decaying modes:Frequency and horizontal slowness are common to all modes, by translation invariance of the surface. Zero surface traction imposes the three equationsHence the free-surface anisotropic reflection amplitudes arewhenever is invertible. This specifies mode conversion as well as reflection. If is singular, a nonzero outgoing homogeneous surface mode exists; these are surface-wave poles, including Rayleigh waves in the isotropic case. At such parameters one must use the appropriate limiting radiation solution and check solvability instead of assuming a unique finite inverse.
Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 47 7 Solution Created 2026-10-03 Updated 2026-10-14
Let the surface radius be , let denote epicentral angle in radians, and put . The spherical elastic ray invariant gives . Along either radial leg, if is arclength and polar angle in the ray plane,For a turning ray with minimum radius defined by , the outgoing and incoming legs therefore giveThe square-root turning singularity is integrable for a regular turning point.
Introduce the reduced travel timeIts integrand vanishes at the moving lower endpoint, so differentiation gives . Consequentlyon every regular travel-time branch. This is also the endpoint variation of travel time: the tangential endpoint slowness multiplied by the surface radius is . Angles expressed in degrees would introduce the corresponding conversion factor; the displayed equality uses radians.
For Herglotz–Wiechert inversion, assume is strictly increasing so that is single-valued, and set and . The angular integral becomes an Abel integral equation:For any , multiply by and integrate. Interchanging the triangular region givesThe inner integral equals : the substitution reduces it to . Thus the full constructive inversion isThe surface radius and surface slowness fix the normalization. Varying reconstructs radius and speed parametrically; the centre is recovered by a limit when the data extend that far. The calculation assumes smooth regular turning rays and complete branch data, not merely the first arrival at each epicentral angle.
If decreases outwards on an interval, then it increases as a surface ray travels inward through that interval. Such a ray cannot turn there, since turning requires the decreasing inward value of to reach . Rays that penetrate this interval can traverse it and turn deeper, but the map now has several branches. The angular data constrain combinations of those branch contributions, rather than the single function used above. This is a hidden turning-ray zone from nonmonotone spherical slowness. The stated single-valued inversion fails and does not uniquely locate the speed profile in that interval without additional information. Missing turning rays and possible multiple travel-time branches are the obstruction, not a failure of the algebraic Abel-kernel identity.
Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 54 1 Solution Created 2026-10-03 Updated 2026-10-14
Because is arc length, . Thus , where is the unit tangent to the elastic ray. In an isotropic medium this is also the wavefront normal. Consequently is the vector slowness, of magnitude ; locally , with the travel time and the wavevector.
For depth-dependent wave speed , the ray equation gives . The horizontal component of therefore has a fixed direction, and the elastic ray lies in the vertical plane determined by that direction and its initial point. A vertical elastic ray is the limiting case. If is the angle to the vertical, its conserved horizontal slowness givesAt a horizontal interface, matching the tangential wavevector at fixed frequency gives the same invariant on both sides: this is Snell's law.
For radial wave speed , take the cross product of position with slowness. The ray equations givesince the second vector is radial. A nonzero constant is perpendicular to every position on the elastic ray, so the ray lies in a fixed plane through the centre. Radial rays obey the same conclusion with a nonunique plane. The spherical elastic ray invariant is thereforewhere is measured from the radial direction. Across a spherical interface the radius is common and tangential slowness is continuous, so this form of Snell's law survives an interface discontinuity.
In a homogeneous sphere a P wave follows the straight chord between the two surface points. If their principal angular separation is , its length is . For constant P wave speed ,Now put and denote the mantle and core P wave speeds by . Equal incidence and reflection angles put the core-boundary reflection point on the angular bisector. Each mantle leg has length given by . Hence the core-reflected travel time isThe stated domain is essential. At the reflection point the incoming line approaches from the mantle only if . Otherwise it has already crossed the core boundary. The mantle-only direct chord also exists only for , with . In this interval,so the reflected arrival is later. Its intercept is , whereas the direct intercept is zero. At grazing incidence the branches meet at , and both have slope . A continuation of the homogeneous-sphere direct formula beyond this endpoint is not a mantle-only arrival in the modified model.
The core-transmitted elastic rays consist of three straight legs. Their impact distances in mantle and core are and , respectively. At core entry,Since , the elastic ray bends towards the normal on entry and away from it on exit. The mantle leg subtends at the centre, and the core chord subtends . Thus the total angular sweep along the transmitted path is . This sweep need not equal the principal separation if it exceeds ; the diagram uses a path with sweep below .
Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 54 3 Solution Created 2026-10-03 Updated 2026-10-14
For a homogeneous lossless elastic solid, insert the plane wave into the equations of linear elasticity. Put , , and . The resulting eigenvalue problem isThe minor and major symmetries make this acoustic tensor a real symmetric matrix. For a stable material it is positive-definite, so its three positive eigenvalues give three real positive phase velocities and therefore three slownesses . Coincident eigenvalues are possible, so there need not be three distinct speeds. For distinct eigenvalues the displacement polarization are orthogonal; in an anisotropic solid they are generally quasi-longitudinal and quasi-transverse rather than exactly longitudinal and transverse. Stability, or at least strong ellipticity in elasticity, is required for the assertion about positive real speeds.
The elastic slowness surface is the locus of the three vectors . Its equation isFor each wavefront normal there are three radial sheets, which may meet at degeneracies. To obtain the energy flux directly, multiply the elastic equation by . Forthe symmetry of stress gives . Thus the instantaneous elastic-wave energy flux is . With a real branch polarization , harmonic averaging givesNow differentiate along a regular slowness surface sheet and contract with . The terms containing cancel by symmetry and the original eigenvalue equation, leavingEvery tangent is consequently perpendicular to : the energy flux is normal to the slowness surface. At a degenerate point this statement is made on the limiting branches, rather than assuming a unique normal.
For completeness, equality of the mean kinetic and strain energies gives . Differentiating the acoustic tensor equation in the wavevector variables similarly givesThus the group velocity is the elastic energy velocity. The homogeneous elastic dispersion relation is degree one in , so differentiating at gives .
The elastic wave surface is the unit-time locus of these group velocities. From an impulsive point source, the propagating wavefronts at time are its sheets scaled to . A particular source may fail to excite a mode in some directions, and its amplitudes require the source polarization and geometrical spreading; the wave surface determines the arrival geometry. It does not specify all near-field motion between the radiative fronts. Geometrically it is the envelope of the planes : tangent variation gives , so is the appropriately normalized normal to the slowness surface.
In a symmetry-plane cross-section write , and . The two envelope conditions giveThe numerator is the signed curvature numerator of the slowness surface cross-section. At a simple inflection point, and . Then and are linearly independent. These are precisely the local conditions for an ordinary cusp. The slowness curvature and wave-surface cusps relation explains why a smooth nonconvex slowness surface can generate a cusped wavefront and multiple ray arrivals.
The example below uses a positive orthotropic stiffness in normalized units: , , , , and all normal off-diagonal stiffnesses zero. In the symmetry plane , its two in-plane acoustic tensor eigenvalues are , and its out-of-plane shear speed is . The in-plane shear sheet is nonconvex and produces the marked cusps; the construction uses an actual stable elastic tensor.
Slowness 2026-10-14
Slowness is the reciprocal of phase velocity, measured in time per distance. A plane wave with wavevector and angular frequency has vector slowness . Its direction is the wavefront normal, which need not be the group velocity direction in an anisotropic medium.
Spherical elastic ray invariant 2026-10-14
For an isotropic radial wave speed , the elastic ray equations imply conservation of , where is the slowness vector. Indeed, its derivative is . Thus each nonradial elastic ray lies in a fixed plane through the centre and is constant. The angle is measured from the radial direction; tangential slowness continuity preserves across spherical interfaces.
Travel time 2026-10-14

