Past exam of the mathematics course of the University of Cambridge 2005 ia Paper 2 10F Solution Created 2026-09-24 Updated 2026-09-24
Past exam of the mathematics course of the University of Cambridge 2014 ia Paper 2 12F Solution Created 2026-09-24 Updated 2026-10-06
An exponential distribution of rate has density for and zero for , with survival probability . For , its memoryless property follows fromFor the minimum, independence gives . HenceThe density is zero for negative . The comparison probability follows from identical continuous laws and zero tie probability; directly it is . These are competing exponential clocks.
For the last density, substitute into the normalizing integral to obtain , the Gaussian integral. Equivalently, each variable has a gamma distribution with shape and rate one. Independence permits convolution of the densities. For ,Putting turns the integral into . ConsequentlyThis is also the additivity of independent gamma distributions with a common rate: their shapes add to one. Density values at the single endpoint zero are immaterial.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 207 3 g Solution Created 2026-10-03 Updated 2026-10-06
Initially, the infection and recovery transition intensities are and . By competing exponential clocks, the first-event waiting time has distribution
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 207 3 h Solution Created 2026-10-03 Updated 2026-10-06
The first event causes extinction precisely when it is recovery of the sole initially infectious individual. An infection would instead give two infectious individuals. The competing exponential clocks calculation therefore gives the first-event extinction probability
Past exam of the mathematics course of the University of Cambridge 2023 ia Paper 2 11F a Solution Created 2026-09-24 Updated 2026-10-03
Past exam of the mathematics course of the University of Cambridge 2024 ia Paper 2 9F i Solution Created 2026-09-24 Updated 2026-09-25
Put . Since the variables have continuous distributions, the minimum is unique almost surely. Integrating over its possible value givesThis is the joint tail calculation for competing exponential clocks.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 207 1 e i Solution Created 2026-09-24 Updated 2026-10-03
The two event clocks have independent exponential distributions with rates and . The competing exponential clocks identity gives