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Each Killing vector field supplies a conserved quantity for freely moving test particles: it turns a geometric symmetry into a first integral of the geodesic equation. Let $\gamma (\lambda )$ be a geodesic with affine parameter $\lambda$, tangent vector $U^{\mu }=d{x}^{\mu }/d\lambda$, and ${\nabla }_{U}U=0$. Wherever a Killing vector field $K$ is defined along the geodesic,The statement applies to Riemannian manifolds and to timelike geodesics, null geodesics and spacelike geodesics in a Lorentzian manifold. It requires an affine parameter; for a massive test particle, proper time is one choice. See Tong, section 4.3.2, equation (4.32).

For a worked example in the Euclidean plane, take $\gamma (t)=(1+t,2-t)$ with affine parameter $t$ and velocity $U=(1,-1)$. The Euclidean Killing vector fields for translation and rotation giveThe rotational field along the geodesic is $K_{\mathrm{rot}}(\gamma (t))=(t-2,1+t)$: it changes from $(-2,1)$ at $t=0$ to $(-1,2)$ at $t=1$, yet its pairing with $U$ stays $-3$. With toy mass $m=1$ and $t$ interpreted as time, the first constant is the $x$ component of linear momentum, and the second is the signed $z$ component of angular momentum about the origin. Their numerical values use toy units. The geodesic is straight; the rotation flow orbits are circles.

This conservation law follows from metric compatibility and the Killing equation:The geodesic equation kills the acceleration term, and the symmetric product $U^{\mu }{U}^{\nu }$ selects the vanishing symmetric derivative. This tensor contraction is the whole proof outline; see Carroll, equation (5.43).

In a stationary spacetime, a chosen time-translation Killing vector field $K$ gives Killing energy. With metric signature $(-+++)$, $c=1$, and a massive test particle's four-momentum $p^{\mu }=m{U}^{\mu }$, the physical normalization isHere $\Phi$ generates the axial rotational symmetry when one exists. In coordinates with $K={\partial }_t$ and $\Phi ={\partial }_{\varphi }$, these are $E=-p_t$ and $L_z=p_{\varphi }$. Both are conserved quantities along the geodesic, even if the metric has a time-angle cross term. A future timelike $K$ makes $E$ positive for a future massive particle; the scale of $E$ depends on the normalization of $K$. Not every spacetime has a global timelike Killing vector field, and a stationary field can become spacelike in an ergoregion of a stationary spacetime. Conservation on the field's domain does not imply a universal global positive energy; see Tong, sections 4.3.1-4.3.2 on the timelike-domain qualification and conserved charges.

An asymptotically flat spacetime is a stationary spacetime if it admits a complete stationary Killing vector field $K$, with ${\mathcal{L}}_{K}g=0$, timelike near infinity and normalized there to a unit time translation. It need not remain timelike in an ergoregion of a stationary spacetime. It is axisymmetric if it admits an axial Killing vector field $\Phi$, whose flow is a rotational $U(1)$ action: its spacelike orbits away from the axis are closed with period $2\pi$, and it vanishes on the regular rotation axis. For a stationary axisymmetric spacetime, the generators can be chosen to commute, $[K,\Phi ]=0$. These are geometric symmetries, not merely time-independent or angle-independent coordinate labels.

Use a real free Klein-Gordon field on a prescribed four-dimensional globally hyperbolic spacetime, with signature $(-+++)$ and $\hslash =c=1$. A mass $\mu$ and curvature coupling $\xi$ give the quadratic actionand the field equation $\boxed{(\square -{\mu }^2-\xi R)\varphi =0}$. Minimal coupling is $\xi =0$; for a massless scalar in four dimensions, conformal coupling is $\xi =1/6$. Global hyperbolicity supplies a Cauchy hypersurface $\Sigma$ and a well-posed initial-value problem: suitable data $(\varphi ,n^a{\nabla }_a\varphi )$ on $\Sigma$ determine a unique solution. One assumes appropriate support or decay conditions so no unaccounted flux crosses spatial infinity. The geometry is classical here; quantum backreaction is a further problem.

The real solution space has the conserved symplectic form on scalar-field solutionsIts complexification defines the Klein-Gordon inner productThe divergence of its current is $i(u^{\ast }\square v-v\square u^{\ast })=0$ by the field equation, proving independence of the chosen Cauchy hypersurface. This Hermitian form is not positive definite on the whole complex solution space: conjugating a solution reverses its norm.

Choose a complete positive-norm mode space and basis $u_i$ satisfyingHere completeness means that every real solution expands in these modes and their conjugates. Equivalently, one chooses a compatible complex structure on the Klein-Gordon solution space; this is extra data, not fixed by the field equation. Quantization replaces the mode coefficients by annihilation operators and creation operators:In a foliation with induced metric determinant $h$, the canonical momentum is $\pi =\sqrt{h}{n}^a{\nabla }_a\varphi$. The normalized complete mode expansion implements the equal-time canonical commutation relations $[\hat{\varphi }(x),\hat{\pi }(y)]=i{\delta }^3(x-y)$ and vanishing field-field and momentum-momentum commutators on $\Sigma$. Propagation by the field equation gives microcausality: field observables commute at spacelike separation. Thus there is a local quantum field theory before one has selected a particle interpretation.

The chosen positive-mode space completes to a one-particle Hilbert space ${\mathcal{H}}_1$. Its bosonic Fock space is ${⨁}_{n=0}^{\infty }{\mathrm{Sym}}^n{\mathcal{H}}_1$. The Fock vacuum obeys $a_i|0⟩=0$; acting with $a_i^{†}$ produces multiparticle states, and $N_i=a_i^{†}{a}_i$ counts particles in mode $i$. The vacuum two-point function is $W(x,y)={\sum }_i{u}_i(x)u_i(y{)}^{\ast }$. The Hadamard condition restricts physically admissible states by prescribing their local short-distance singularity; it permits renormalization of the stress-energy tensor but does not select one unique vacuum.

The particle ambiguity is that there is generally no distinguished choice of positive-mode space. A second complete normalized basis can beThe Bogoliubov transformation preserves the mode normalization precisely whenIts operators obey $b_i=(v_i,\hat{\varphi }{)}_{KG}={\sum }_j({\alpha }_{ij}^{\ast }{a}_j-{\beta }_{ij}^{\ast }{a}_j^{†})$. Consequently a state with no $a$-particles generally has $b$-particles if $\beta \ne 0$. A unitary change of basis within the same positive-mode space has $\beta =0$ and merely relabels modes; a change mixing the positive and negative subspaces changes the vacuum and particle notion. Arbitrary coordinates called “time” do not resolve this choice. This is the vacuum ambiguity in a nonstationary spacetime, while the field equation and local commutator remain unchanged.

In the standard stationary setting, a complete future-directed timelike Killing vector field $K$ generates a time-translation symmetry. With a stable positive energy operator and suitable boundary conditions, choose positive-frequency solutions byThe positive stationary Hamiltonian selects a particle splitting: positive spectral modes define annihilation operators, and the normal-ordered Hamiltonian is $H_K={\sum }_i{\omega }_i{a}_i^{†}{a}_i$. Its ground state is the vacuum state in a stationary spacetime. The Killing symmetry transports this splitting unchanged, so no positive-negative mixing is induced by stationary evolution. Degeneracies allow unitary basis changes without changing the vacuum. Stationarity fixes the ground-state particle interpretation relative to this time flow; it does not forbid excited or thermal states.

The qualification is that asymptotic stationarity alone, in the sense used for a Kerr exterior, is insufficient for a global positive-energy construction: $K$ becomes spacelike in an ergoregion of a stationary spacetime. The usual unambiguous construction applies to a strictly stationary spacetime with the stated stability and spectral assumptions, or to appropriate stationary asymptotic regions for scattering. Zero modes or instability need separate treatment. Likewise different observer time flows on different regions need not define the same particles.

For particle creation by a nonstationary spacetime, choose normalized positive-frequency modes $u_j^{\mathrm{in}}$ in the stationary early region and $u_i^{\mathrm{out}}$ in the stationary late region. Propagate both sets by the Klein-Gordon equation through the intermediate time-dependent geometry. Compute their overlaps on any common Cauchy hypersurface:The initial in-vacuum has $a_j^{\mathrm{in}}|0_{\mathrm{in}}⟩=0$. Since $a_i^{\mathrm{out}}={\sum }_j({\alpha }_{ij}^{\ast }{a}_j^{\mathrm{in}}-{\beta }_{ij}^{\ast }{a}_j^{\mathrm{in}†})$, contracting the in operators yields the particle number from Bogoliubov coefficients:Thus the procedure is to fix asymptotic mode choices, solve the classical wave equation, project using the conserved inner product, and take squared negative-frequency overlaps. Particle energy comes from the time-dependent background, so particle creation does not contradict the linear deterministic field equation. For an initial state diagonal in in-mode occupation numbers $n_j$, with no anomalous correlations, the more general expectation is ${\sum }_j[|{\alpha }_{ij}{|}^2{n}_j+|{\beta }_{ij}{|}^2(n_j+1)]$.

For continuous spectra, sums become integrals and normalized wave packets avoid meaningless squares of delta functions. A finite total count requires the appropriate convergence of the double sum or integral. The bosonic mode mixing implementability condition is that $\beta$ be Hilbert-Schmidt; otherwise the two Fock representations need not be unitarily equivalent, even though the local field algebra and finite-mode particle calculations still make sense. This distinction between deterministic field evolution and a chosen representation is essential to quantum field theory in curved spacetime.

An ergoregion of a stationary spacetime is where the stationary Killing vector field, normalized as time translation at infinity, is spacelike; a fixed-coordinate stationary observer cannot remain timelike there. For the Kerr metric, $k^2=-(1-2Mr/\Sigma )$, so the outer stationary-limit surface isFor a subextremal rotating hole $r_{\mathrm{E}}\ge r_{+}=M+\sqrt{M^2-a^2}$, with equality only at the poles. At the equator $r_{\mathrm{E}}=2M>r_{+}$. The ergosphere touches the horizon on the rotation axis and is outside it elsewhere. Its boundary is not the horizon, whose generator is $k+{\Omega }_{H}m$.

The drawing uses oblate Cartesian coordinates to display the intersection and is not an isometric embedding of the spatial geometry.

For a stable free Klein-Gordon field with a complete timelike Killing flow and a positive self-adjoint one-particle energy generator, its positive spectral subspace selects positive-frequency solutions of positive Klein-Gordon inner product. Their annihilation operators define the ground-state Fock vacuum. Degenerate modes can be mixed by a unitary matrix without changing this splitting or vacuum. Merely being stationary near infinity is insufficient if the Killing field becomes spacelike in an ergoregion of a stationary spacetime; zero modes, instability or additional boundary conditions also require separate treatment. The choice of a ground state does not prevent other states, such as thermal states, from using the same particle operators.

// Target: statistical-physics.bigb