Bigness under finite normalization 2026-10-05
Let be the finite normalization of an integral projective variety. The coherent sheaf is supported in dimension at most . For a Cartier divisor , the projection formula for sheaves and the resulting long exact sequence in sheaf cohomology giveThe last step uses the polynomial bound for sections of a fixed divisor. Therefore the leading order growth, and hence bigness, is preserved in both directions. This handles nonnormal varieties without assuming a resolution of singularities in positive characteristic.
On an irreducible variety, a Cartier divisor is a section of : its local rational equations differ by regular units. Their ratios define an invertible sheaf, and a global rational equation gives the trivial class. Conversely a rational trivialization of an invertible sheaf gives local equations. The rational-function sheaf is flasque, so its long exact sequence in sheaf cohomology also identifies the quotient with .
Cotangent-sheaf cohomology of projective space Created 2026-10-07 Updated 2026-10-14
For , the cotangent form of the Euler sequence is . The cohomology of twisting sheaves on projective space and the long exact sequence in sheaf cohomology give , with every other cohomology group zero. Therefore the Euler characteristic of a coherent sheaf is . The nonzero class is the connecting image of the constant section .
Divisor class group and Picard group of a smooth curve Created 2026-10-05 Updated 2026-10-06
For a smooth irreducible algebraic curve, send a divisor on an algebraic curve to the line bundle associated to a divisor defined locally by . A nonzero rational section of a line bundle gives its inverse construction, and changing that section changes its divisor by a principal divisor. Thus the divisor class group is the Picard group. The quotient of the sheaf of nonzero rational functions on an irreducible variety by the sheaf of units of the structure sheaf has stalk at each closed point, via the discrete valuation. Its global sections are finite sums of points. The corresponding long exact sequence in sheaf cohomology, and the vanishing for the rational-function sheaf, identify both groups with .
Divisor restriction exact sequence Created 2026-10-05 Updated 2026-10-06
For an effective Cartier divisor and any Cartier divisor , multiplication by a defining section of gives the displayed short exact sequence of sheaves. Its long exact sequence in sheaf cohomology compares sections and cohomology on with their restrictions to .
Flasque-kernel section-lifting lemma Created 2026-10-05 Updated 2026-10-14
For a short exact sequence of sheaves with flasque sheaf kernel, every section of the quotient on any open set lifts to the middle sheaf on that set. Use the Zorn lemma to choose a maximal partial lift, with chains glued by the sheaf gluing axiom. A new local lift differs from the old one on their overlap by a kernel section. Extend that difference by flasqueness, adjust the new lift, and glue, contradicting maximality unless its domain is the entire open set. Consequently a quotient of two flasque sheaves is flasque. With an injective resolution of sheaves, the long exact sequence in sheaf cohomology and repeated dimension shifts prove that flasque sheaves have zero positive-degree cohomology.
For a hyperplane with inclusion , multiplication by its defining linear homogeneous polynomial gives the short exact sequence of sheavesThe long exact sequence in sheaf cohomology relates twists in consecutive degrees and consecutive dimensions. Surjectivity of restriction on global homogeneous polynomials, together with eventual positive-twist vanishing, proves vanishing of intermediate cohomology by descending induction. The top-degree dimensions satisfy for , where .
Ideal sheaf of two closed points 2026-10-06
For distinct closed points over an algebraically closed field, evaluation gives the short exact sequence . If all global regular functions are constant, the long exact sequence in sheaf cohomology embeds into . Thus this ideal detects a concrete obstruction to affineness.
If for every coherent ideal sheaf, projection to the last coordinate makes any coherent an extension of a coherent submodule of by an ideal sheaf. The long exact sequence in sheaf cohomology proves the assertion by mathematical induction on .
For a length- projective complete intersection , the groups vanish for every integer and . Starting with cohomology of twisting sheaves on projective space, induct through . Both adjacent groups in the long exact sequence in sheaf cohomology vanish precisely in the indicated range.
For , these sheaf cohomology dimensions follow from the vanishing for and the hyperplane exact sequence for twisting sheaves. Induct on dimension and then on in . The long exact sequence in sheaf cohomology gives higher-degree vanishing and the recurrence . Starting with yields the formula; the corresponding homogeneous monomials form a basis of global sections.
Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 15 1 Solution Created 2026-10-03 Updated 2026-10-14
At a point , the complex tautological line bundle has fiber . The hyperplane line bundle is its dual, , and . On let be the tautological frame and its dual. On overlaps . The sheaf of holomorphic sections of a vector bundle of this dual bundle is the sheaf .
If a nonzero linear form cuts out the projective hyperplane , it gives a holomorphic section of with a simple zero along . Dividing a local section by gives a meromorphic function with no poles away from and at most a simple pole on . Conversely multiplication by turns such a function into a holomorphic section. These mutually inverse local constructions agree on overlaps and prove the holomorphic line bundle associated to a divisor identification
The nonnegative hyperplane twist cohomology by restriction calculation givesTo derive it from the permitted vanishing, use the hyperplane exact sequence for twisting sheaveswhere and . Local multiplication by a defining equation is injective, and restriction gives exactly its cokernel. Induct on , starting from a point, and then on . For , higher sheaf cohomology vanishes by assumption and global holomorphic functions are constant by compactness and the maximum principle. For , the long exact sequence in sheaf cohomology, the inductive vanishing for and the dimension induction on give vanishing in every positive degree andSumming this recurrence gives . Homogeneous degree- monomials give that many independent sections, so they form a basis. The printed extra equality to zero cannot hold in degree zero, already because ; the boxed calculation gives the intended dimensions.
For the differential of the projective quotient map, the differential of a smooth map is computed by applying a tangent vector to coordinate functions. Since ,ThusUnder replacing by , on a constant ambient tangent vector scales by , while a homogeneous linear form scales by . Therefore is independent of the representative. Its chart coefficients are holomorphic, so it is a global holomorphic vector field. The radial Euler vector field lies in the kernel of , either from the same formulas or because it differentiates a scaling orbit. Hence
Describe the Euler sequence on complex projective space fiberwise as well as in coordinates. At a line , the middle bundle has fiber and the holomorphic tangent bundle has fiber . Send a homomorphism to its composition with the quotient. The map from sends a scalar to that scalar times the inclusion . In homogeneous notation these maps areA local section of is a local degree-one homogeneous function on the punctured cone, so the second expression is representative-independent. Quotienting is surjective, and its kernel consists exactly of scalar inclusion maps. This proves the short exact sequence of locally free sheavesSince it is locally split, dualizing and tensoring by preserves exactness and gives the cotangent Euler sequence in homogeneous coordinatesOn global sections the last map identifies with the basis of linear forms in . Its kernel is zero. This proves the vanishing of global sections of the once-twisted projective cotangent bundle; left exactness gives .
Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 15 4 Solution Created 2026-10-03 Updated 2026-10-14
Let be a separated Noetherian scheme over a field and a coherent sheaf. Coherent cohomology studies the groups : global sections in degree zero and the obstructions to gluing local sections in higher degrees. Coherence means finite generation locally, and on a Noetherian scheme it is preserved by kernels, cokernels and extensions. This makes coherent sheaves suitable for exact-sequence calculations.
For an ordered open cover , the Čech cochain groups arewith differentialEach double omission occurs twice with opposite signs, so . The Čech cohomology of the cover is , and taking the direct limit over refinements defines cover-independent Čech cohomology. In degree zero the sheaf gluing axiom identifies it with .
The comparison with derived-functor sheaf cohomology is particularly effective algebraically. Positive-degree cohomology of a quasi-coherent sheaf on an affine scheme vanishes. A separated scheme has affine intersections of affine opens, so a finite affine cover is acyclic for . Its Čech cochain complex consequently computes directly. For a short exact sequence of sheaves, sections over each affine intersection are exact on quasi-coherent sheaves. The resulting short exact sequence of Čech complexes gives the long exact sequence in sheaf cohomology. In particular, the connecting map measures the failure of a global section of the quotient to lift globally.
Several central projective results make the theory finite and computable. On a projective variety over , every coherent cohomology group is finite-dimensional. The Grothendieck vanishing theorem gives for . If is ample, Serre vanishing gives for sufficiently large , and these large twists are globally generated sheaves. On projective space a coherent sheaf has a finite twisting resolution of a coherent sheaf on projective space: finite sums of resolve it. The explicit line-bundle cohomology below and the long exact sequences prove finiteness and positive-twist vanishing. For a closed embedding , is coherent and , reducing these results to projective space. A sufficiently positive twist of a finite presentation by sums of also proves global generation.
The Euler characteristic of a coherent sheafis therefore defined, and the long exact sequence makes it additive. With a fixed projective embedding, is its Hilbert polynomial, and for sufficiently large it equals . On a smooth projective variety of dimension , Serre duality gives, for a vector bundle ,For an arbitrary coherent sheaf the correct counterpart is ; replacing this Ext group indiscriminately by the cohomology of the ordinary sheaf dual would lose local extension information.
We now calculate the basic examples. For , use the standard cover of . Sections of on an intersection are degree- Laurent monomials in which negative exponents are allowed only for coordinates inverted on that intersection. Decompose the Čech cochain complex by exponent vectors with sum . If no exponent is negative, the corresponding simplex complex contributes only in degree zero. If all exponents are negative, the monomial occurs only on the full intersection and contributes only in degree . When the negative-index set is nonempty and proper, inserting any index outside it gives a contracting homotopy, so the monomial complex is acyclic. Hence the cohomology of twisting sheaves on projective space isIn the top group a basis consists of the Laurent monomials with every exponent at most . Writing reduces the count to nonnegative solutions of , giving the displayed binomial coefficient. In particular, all intermediate cohomology vanishes, and agrees with Serre duality. For separately, every twist is trivial and .
On the projective line this givesThus positive and negative degrees produce quite different groups, while their alternating difference is a single polynomial. The twisted cubic is isomorphic to and its hyperplane bundle corresponds to . Consequently for , agreeing with Q2, and .
For a smooth plane curve of degree , the ideal-sheaf sequence of a projective hypersurface isThe long exact sequence in sheaf cohomology and the preceding formula give and . ThereforeFor this is zero; for a plane cubic it is one. Twisting the same exact sequence gives . These examples illustrate how Čech cohomology, vanishing, Serre duality and exact sequences convert local equations into global numerical invariants.
Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 21 4 Solution Created 2026-10-03 Updated 2026-10-14
Let be the smooth algebraic curve. A nonzero regular section of a line bundle has an effective zero divisor, so its degree of a line bundle is nonnegative. Degrees add under tensor products and change sign on taking the dual. We use genuine line subbundles, so their quotients in are locally free. Both bounds can be proved constructively.
For the upper bound, take a rational frame of over the function field of . Its two members are rational sections with only finitely many poles. Choose an effective divisor large enough to bound the pole orders of both rational sections. They become global sections of and define a sheaf mapwhich is an isomorphism at the generic point. It is therefore injective as a sheaf map: a section in its kernel would vanish generically in a locally free sheaf, which is a torsion-free sheaf. For any line subbundle , at least one of its two component maps into is nonzero. Such a map is a nonzero global section of . Its zero divisor on an algebraic curve is effective, soThis upper degree bound for line subbundles on a smooth curve depends only on a choice made for , and applies to every one of its line subbundles.
For the lower-bound question we will actually construct subbundles for every sufficiently large integer , where is a fixed point. First prove the globally generated vector bundle property rather than assuming that negative-degree inclusions automatically are subbundles.
Apply the upper-bound argument to the rank-two vector bundle , where is the canonical bundle. Let be its upper degree bound. Choose with . For any point , a nonzero global section of would give a nonzero mapIts image can be saturated to a saturated line subbundle on a smooth curve . Locally the local ring of a smooth algebraic curve is a discrete valuation ring: dividing out the common power of a uniformizer makes the image a primitive rank-one summand, and its quotient is free. Thus the saturation is indeed a subbundle. The original map gives a nonzero global section of and consequently , contradicting the upper bound. Hence for every . By Serre duality,The exact sequenceand its long exact sequence in sheaf cohomology show that evaluation is onto for every . This proves the global generation of positive twists on a smooth curve with one bound on that works at every point.
Write and . The evaluation map is surjective with kernel bundle of rank . Consider the incidence subsetIt is the total space of this kernel bundle, so . Its projection into is closed because is proper, and its image has dimension at most . Choose outside this proper closed subset. It vanishes nowhere. In a local trivialization at any point, one component of is a unit, so it can be completed to a basis. Therefore is a subbundle with a locally free rank-one quotient. Twisting back givesThis proves the unbounded negative degrees of line subbundles. The nowhere-vanishing construction guarantees a subbundle at every point, including the zeros that might otherwise have occurred in a generic meromorphic inclusion. If the curve has several connected components, apply these constructions on each component and add the degrees; the same upper-bound and no-lower-bound conclusions follow.
Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 80 4 Solution Created 2026-10-03 Updated 2026-10-14
The printed vanishing claim needs the restriction . On with and , Question 3 gives for every . Thus no bound on the degree of a divisor can force vanishing in degree zero. We prove finiteness in every degree and the corrected vanishing in every positive degree, uniformly over all divisors on an algebraic curve of large degree.
First take a finite morphism as in Question 3 and put . The direct image sheaf is coherent: on an affine chart its module is finitely generated over a finite algebra and hence over the chart's coordinate ring. The two affine-cover Čech cochain complexes for on and for on are identical. Therefore
We need an elementary presentation of any coherent sheaf on the projective line. Choose finitely many generators on each of its two standard affine charts. A generator on the first chart restricts to an element of the second chart's module localized at . Multiplication by a sufficiently large power of brings that element into the second chart's module. Since the transition of is , this makes the original generator extend to a global section of . A generator on the second chart similarly extends after clearing its denominator at . Use one common exponent for all the finitely many generators. The extended sections generate on both charts. Untwisting gives a surjectionwith coherent kernel . The long exact sequence in sheaf cohomology and Question 3 show that is a quotient of the finite-dimensional , since . Apply the same presentation argument to to obtain finiteness of . Then the segment proves finiteness of . Higher groups vanish by Question 3. Hence every is finite-dimensional.
Next establish a useful degree estimate without using the duality requested later. A global regular function on is constant: a nonconstant one would give a finite morphism by Question 1. Such a morphism is surjective, because its closed image contains the generic point, but a regular function misses , a contradiction. Thus . Write , the genus of a smooth projective curve. For any divisor on an algebraic curve and point , the local discrete valuation ring givesThe last term is a length-one skyscraper sheaf. Additivity of the Euler characteristic of a coherent sheaf and repeated addition or subtraction of points giveThe inequality follows because is nonnegative, and is sufficient for the following argument.
Fix . For this estimate gives at least two independent sections of , one of them the constant section. A nonconstant section is a rational function on an algebraic variety whose poles are confined to . It must have a pole there, since a globally regular function is constant. Its extension is finite, and its inverse image of is exactly . Consequently is affine.
Let be the torsion subsheaf of and let . The support of is finite; such a coherent sheaf is a finite direct sum of sheaves supported at points and has zero higher sheaf cohomology. The torsion-free sheaf is locally free: a finitely generated torsion-free module over a discrete valuation ring is free. Tensoring by any invertible sheaf is exact, so
The inclusions have point-supported quotients. Their long exact sequences in sheaf cohomology therefore give surjections on . Moreovera section regular away from has some finite pole order at . Compute this direct limit on a finite affine cover of . All its intersections with are affine by Question 2, and localization commutes with filtered direct limits. The Čech cochain complex consequently givesThe maps from to these groups are surjective. Choose a finite basis of this starting vector space. Each basis vector becomes zero at some stage in the direct limit; one common stage kills the entire basis. Thus there exists with .
Now let be any divisor on an algebraic curve with . The estimate above gives . A nonzero section identifies with an effective divisor up to linear equivalence of divisors. Hence . Adding gives a point-supported quotient of , so its first sheaf cohomology is a quotient of . We have proved uniform high-degree vanishing on a smooth projective curve:This bound concerns all high-degree divisors, not only multiples of a previously chosen divisor.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 14 1 c Solution Created 2026-10-03 Updated 2026-10-14
Since is an irreducible variety, every nonempty open subset is irreducible and the sheaf of nonzero rational functions on an irreducible variety has value there. All its restriction maps between nonempty opens are identities, and restriction to the empty set is surjective. Thus is a flabby sheaf, and the introductory argument gives .
Apply the long exact sequence in sheaf cohomology to the short exact sequence of sheavesIts relevant portion isThe connecting homomorphism is therefore surjective, with kernel the image of . The computation in part (a) now givesConcretely, local rational equations of a divisor on an algebraic curve differ by regular units on overlaps. Their ratios give the gluing data of an invertible sheaf; changing the local equations by units changes those data by a coboundary. This is the transition-function interpretation of the identification with the Picard group. Reversing all transition ratios replaces a class by its inverse; either consistent convention gives the same group isomorphism.
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 14 4 Solution Created 2026-10-03 Updated 2026-10-14
Let with its usual grading, and put . Define the twisting sheaf on projective space byMore explicitly, on its sections are the homogeneous degree- part of . They are a free rank-one module over , with generator . These generators make sense for every integer , since is invertible on this chart. Their transition rule isThe ratios are regular units on overlaps and satisfy the cocycle identity, so they glue to an invertible sheaf. In particular .
For , a global section is a compatible homogeneous degree- rational expression lying in every . Inside the fraction field of ,To justify this, write a fraction in lowest terms in the unique factorization domain . Membership in forces every irreducible divisor of its denominator to be associated with . Since there are at least two nonassociated variables, the denominator must be a unit. ThereforeThe degree- monomials are indexed by nonnegative integers with sum . The stars and bars count givesHere and below, an all-integer binomial shorthand must use the counting convention when , including negative . The polynomial extension of binomial coefficients to negative upper arguments does not give the stated dimensions. In dimension zero, is one point and every is trivial, so its space of global sections is for every ; this case is treated separately.
For a closed inclusion , direct image sheaf formation is exact: its stalk is the original stalk at a point of and zero outside . It preserves flabby sheaves, since restrictions on the target are restrictions between the corresponding open subsets of . Push forward a flasque resolution of ; exactness gives a flasque resolution of , and its complex of global sections is the original one becauseTaking cohomology of these identical complexes proves sheaf cohomology under a closed inclusion:This argument applies even without quasi-coherence.
We derive the remaining sheaf cohomology dimensions using the given eventual vanishing, the long exact sequence in sheaf cohomology, and induction on dimension. Multiplication by the linear equation of a hyperplane gives the hyperplane exact sequence for twisting sheavesExactness can be checked in each chart by quotienting its polynomial ring by the equation of ; multiplication is injective because that equation is a non-zero-divisor. We use the closed-inclusion cohomology identification to replace the cohomology of the final sheaf by that on .
The dimension-zero base is a point, whose global-section functor is exact. Thus all its higher sheaf cohomology is zero. For , the relevant long exact sequence isWhen , restriction of homogeneous polynomials to the hyperplane point is surjective: after choosing that point as , the section restricts to a generator. Therefore the consecutive groups are isomorphic for . The given vanishing for large propagates down to . For , both displayed groups are zero, and the sequence becomesStarting with , induction downward gives for . For degrees , the point contributes no cohomology to the exact sequence, so consecutive groups are isomorphic for every ; the given eventual vanishing makes them all zero. Hence the complete positive-degree formula holds for .
Now let and assume the formulas for . For every , the restrictionis surjective: for extend a polynomial in the hyperplane coordinates to the same polynomial on , and for both groups vanish because has positive dimension. Consequently the exact sequence gives an injectionFor , the induction hypothesis says , and gives the same injection in degree . For each fixed , composing finitely many injections reaches a sufficiently large twist, whose higher cohomology is zero by the given hypothesis. ThereforeFor , the two neighbouring hyperplane groups and are zero by induction. Consecutive groups on are then isomorphic, and eventual vanishing again makes them zero. This derives vanishing above the dimension too, without needing a special projective-space cohomology theorem.
For top cohomology the exact sequence now reduces toWrite . The induction hypothesis and eventual vanishing give the recurrenceConsecutive top groups agree for , so descending from a large twist gives for . Below this range, iterating the recurrence gives a finite sum:The last equality follows by summing Pascal's identity. These short exact sequences also prove that every group whose dimension is being counted is finite-dimensional. Thus, for ,With the stated counting convention, the latter is the requested single binomial formula. The base has for all twists and no higher cohomology; it is not governed by the negative-twist rule for positive-dimensional projective space.
Finally calculate the canonical line bundle of a smooth variety from its transition functions. On write for . On , , take the coordinates in increasing order of . ThusIn their wedge product, and
. Every term involving a second vanishes, so reordering the remaining differentials givesThis computation is valid in every characteristic. Multiply the ordered local generator on by . The resulting generators satisfy on , and hence the corresponding transition rule on every overlap. They are exactly the transitions of . Therefore the canonical bundle of projective space is
. Every term involving a second vanishes, so reordering the remaining differentials givesThis computation is valid in every characteristic. Multiply the ordered local generator on by . The resulting generators satisfy on , and hence the corresponding transition rule on every overlap. They are exactly the transitions of . Therefore the canonical bundle of projective space is
For a line bundle, Serre duality statesThe intermediate groups on both sides vanish. In the two outer degrees, the top group at twist has the same dimension as the global-section group at twist :The polynomial degree on the right is nonnegative precisely when , and its dimension is . Interchanging and checks the other outer degree. On both sides are one-dimensional. Thus all the formulas are consistent with Serre duality, which was used only for this final consistency check, not to prove the cohomology formulas.
Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 17 4 Solution Created 2026-10-03 Updated 2026-10-14
On the standard affine charts , use the formal frame and glue rank-one free sheaves byThe transition functions are regular units on overlaps and satisfy the cocycle identity. This constructs the twisting sheaf on projective space as an invertible sheaf for every integer , including negative .
On a nonempty , a section has local expressions , where . Pulling to the punctured affine cone gives . Their agreement on overlaps makes them one homogeneous rational function of degree , regular on . To make its polynomial representation explicit, write one nonzero local coefficient as in the affine coordinates. Homogenize to degrees ; the resulting rational expression isIf the exponent of is negative, move its power to the denominator. Cancel common factors; the greatest common divisor of homogeneous polynomials can be chosen homogeneous. Thus with coprime homogeneous polynomials, , and .
Conversely, for such a homogeneous rational function regular on , its coefficient is regular on : restrict to the slice . These coefficients obey the displayed transition rule and hence define a section. This proves the homogeneous rational sections of a twisting sheaf description in both directions, for arbitrary open rather than only a standard chart.
Now lift a regular degree-zero rational function to the punctured cone. The quotient rule givesThis is a rational function homogeneous of degree . It is independent of the chosen representation because differentiation is a derivation of the rational function field. It is regular wherever is regular: a derivation of a polynomial ring extends to each localization by the quotient rule, and regular functions are locally such fractions. The preceding homogeneous-section description therefore provesZeros of a particular displayed denominator do not invalidate this argument; regularity is a property of the rational function, which can have another local representation.
The map is a -linear sheaf derivation with values in . The universal property of Kähler differentials consequently definesMultiplication by the coordinate section defines the other mapFor a degree- homogeneous polynomial, differentiating each monomial gives . Applying this to the equal-degree numerator and denominator gives for degree-zero , so . This identity is valid in every characteristic.
To prove all the exactness assertions, fix and put for . The Kähler differential sheaf is free there on , because a derivation of the polynomial ring is determined freely by its values on the coordinates. Trivialize each with frame . In this frame,where now denotes the th coordinate vector of the direct sum. The map is surjective, since its th coefficient is one. Its kernel consists exactly of tuples with , so the displayed vectors form a free basis of that kernel. The map sends the differential basis bijectively to this kernel basis and is therefore injective. Exactness on these charts proves the cotangent Euler sequence in homogeneous coordinatesThe proof uses no division by an integer and hence no characteristic-zero assumption.
For , the cohomology of twisting sheaves on projective space givesIn particular, , , and for every . The long exact sequence in sheaf cohomology of the displayed Euler sequence beginsand gives zero in the remaining degrees. ThusThe nonzero group is generated by the connecting image of the section of . If is admitted, is a point and its cotangent sheaf is zero, so the sole requested group is zero.
Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 18 3 Solution Created 2026-10-03 Updated 2026-10-14
Let be a smooth projective curve over , let be an effective divisor on an algebraic curve of degree , and identify a translate of the Jacobian variety with . The precise derivative theorem iswhere is the connecting homomorphism ofThe target is under Serre duality. Its dual is restriction of holomorphic differential forms to the length- closed subscheme :In particular, this includes derivatives of the local coefficients at repeated points, rather than simply evaluating once for each point of the support.
Here is a local proof of all these identifications. Near a point of multiplicity , take a coordinate vanishing at that point. Nearby effective divisors are represented by monic polynomials of degree . A first-order deformation has equationThese coefficients are the elementary symmetric coordinates on the symmetric product of a curve; they give independent tangent directions even at a repeated point. Dividing the variation of the equation by the original equation identifies the tangent direction with the principal part . Doing this at each point gives , a space of dimension .
To see the derivative of the line bundle directly, use the local frame for and the frame outside the small disks. Relative to the frame at , its transition multiplier changes byFirst-order changes of line bundle transition functions have the form ; changing frames adds a Čech coboundary. Thus the tangent space to the Picard group is , and the derivative is exactly the Čech cocycle of these principal parts, namely .
This agrees with differentiating the Abel integrals, including the sign. If and , the sum of at the roots of has derivativeFor example, expand . The first-order Newton identities give for , and zero for , yielding exactly the residue above. Equivalently the same formula follows by differentiating the contour integral for the sum over roots. Serre duality pairs the principal part class with by the sum of these residues. Locally this pairing is perfect between the principal parts and the jets times . This proves the asserted dual restriction map.
The long exact sequence in sheaf cohomology now gives the kernel and rank without any reduced-support assumption:By duality,This is the geometric form of the derivative of the Abelian sum map. For distinct points, the image is spanned by the evaluation vectors of the canonical map; at repeated points, the corresponding osculating directions must also be included. The Riemann-Roch theorem confirms the rank as . When , the Abelian sum map is an immersion at . For and , its image is a hyperplane annihilated by the unique nonzero holomorphic differential form vanishing along , which will be the tangent hyperplane to the theta divisor.