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Let $n$ count chromosomes in one complete set, and let $C$ denote the nuclear DNA amount in one unreplicated haploid set of this organism. Ploidy counts sets, whereas $C$ units count material; $C$ is not a universal mass shared by all species. Here we count a paired replicated chromosome as one until its sister chromatids separate. A copied diploid genome is therefore still diploid through S phase: $2n$ persists even as $2C$ becomes $4C$.

An original bookkeeping example uses a hypothetical diploid biological cell with $n=3$. Name its three homologous chromosome pairs $A,a$, $B,b$ and $D,d$. Assume ordinary nuclear DNA replication, no chromosome loss, and one continuous double-stranded DNA molecule per unreplicated chromosome or replicated chromatid. Count nuclear material only, excluding mitochondrion DNA.

For example, $A$ becomes the paired copies $A_1,A_2$ during S phase. They remain one replicated chromosome until separation. Each completed daughter receives one $A$ copy and one $a$ copy, and similarly for the other two pairs. Across both daughters, $2\times 6=12$ double-stranded DNA molecules and $2(2C)=4C$: division allocates the copied material without another round of DNA replication.

The whole undivided anaphase biological cell transiently contains $4n$ separately counted daughter chromosomes. This counting change does not establish a four-set ploidy in a completed daughter genome: each pole receives $2n$, and each completed daughter cell nucleus is diploid. Always state whether a number refers to one cell nucleus, one pole, or the entire undivided biological cell. Compare meiotic DNA content: after meiosis I, a haploid cell nucleus can contain $2C$, so amount alone cannot determine ploidy.

Ploidy counts complete sets of chromosomes in a cell nucleus. Write $n$ for the number of chromosomes in one set: haploid means one set, diploid two. DNA replication produces sister chromatids without changing ploidy.^[ref]

Consider an illustrative species with $2n=6$, hence $n=3$. One set contains three distinguishable chromosome types, $A,B,D$; the diploid cell nucleus contains two homologous chromosomes of each type. Labels describe chromosome identity, not particular alleles. Let $C$ be the Nuclear DNA content of one unreplicated set. All entries below refer to one completed product of division, or the starting cell nucleus, rather than the sum over products. Here “chromatid count” includes the single DNA copy in each unreplicated chromosome.

The arithmetic follows the allocation rules. DNA replication replaces each of six single copies with two associated sister chromatids: $6\times 2=12$ copies still grouped as six chromosomes. Meiosis I allocates one homologous chromosome of every type to each product: three replicated chromosomes, with $3\times 2=6$ copies. Meiosis II allocates one copy from each pair of sister chromatids to each final product: three single-copy chromosomes. Compare meiotic DNA content for the general symbolic bookkeeping. Chromosomal crossover can change the alleles on a chromatid without changing these counts when exchanges preserve material.

Keeping ploidy, chromosome count and Nuclear DNA content separate makes the beauty of meiosis explicit: copying supplies material for two divisions, while sorting determines which complete sets each product inherits. It also prevents interpreting a doubled DNA signal as evidence of an extra homologous chromosome set.