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Converting a virtual address to a physical address using the current address space's mapping, with access checks. In paging, the memory page number changes while the offset within it stays fixed.

Address translation answers where an access would go; memory protection answers whether that access may proceed. Neither answer is the stored value. Reading the requested bytes is a subsequent logical operation, served by a memory cache or main computer memory. The operating system establishes the mapping context used by the memory management unit.^[ref]

Consider an original toy model with unsigned 12-bit virtual addresses, byte addressing, and 64-byte memory pages and page frames. Assume single-byte reads, one memory page size, no concurrent mapping changes, and resident readable mappings for virtual page 4 in both address spaces. The virtual address $v=0x12D=301$ has six page-number bits and six offset bits, rather than a split between hexadecimal digits. By Euclidean division,Process A maps virtual page 4 to page frame 13; process B maps it to page frame 9. Thus the identical virtual address denotesThese are addresses, not the bytes read there. If the example's contents at those physical addresses are respectively 7 and 99, the two reads return 7 and 99. The mapping calculation alone cannot determine either value.

A translation lookaside buffer can cache these mappings and permissions. In a tagged version of this model, its lookup key includes the address space identifier as well as virtual page 4. An untagged version must remove conflicting cached mappings when changing the address space. Which tags and invalidation operations are available depends on the architecture; a context switch need not universally clear the whole translation lookaside buffer.^[ref]

The arithmetic explains the beauty of paging: a mapping can move an entire memory page without changing its internal positions. Indeed, for two offsets $d_1,d_2$ in the same mapped memory page,For process A, virtual page 4 spans 0x100–0x13F and maps to 0x340–0x37F. Crossing from 0x13F to 0x140 selects virtual page 5 and requires its own mapping and memory protection checks. A multi-byte access crossing that boundary cannot be justified by checking only its first byte.

Increasing the number of page frames can increase misses under a given page replacement policy on the same page-reference trace. For FIFO page replacement on the displayed twelve-reference sequence, an empty start with three page frames gives nine misses, while an empty start with four gives ten. The larger run hits only at indices 5 and 6; it misses at 1–4 and 7–12. These are miss counts, not observed running times.^[ref]

The explanation is visible before the final count. After access 6, the three-page frame queue is $(4,1,2)$ and the four-page frame queue is $(1,2,3,4)$, both oldest first. Loading memory page 5 at access 7 removes memory page 4 in the smaller run but memory page 1 in the larger. Their resulting resident sets are $\{1,2,5\}$ and $\{2,3,4,5\}$. The smaller resident set is not a subset of the larger: its next access to memory page 1 hits while the larger run misses. Different earlier evictions create different histories; an extra page frame is not simply an extra unchanged slot. FIFO page replacement can improve on other sequences; the anomaly is an existence claim, not a claim that more page frames usually hurt.

Keep page frames in a circular list with a reference bit and a scanning hand. Clear set reference bits while scanning; choose the first eligible page frame with a clear reference bit. This second chance approximates LRU replacement with cheaper tracking. When hardware reference flags are absent, revoking a mapping and handling its first later page fault can supply a software reference observation.

For the page-reference trace, number the three page frames 1–3 and initially point the hand at 1. Every access sets the referenced page frame's reference bit to 1. On a miss, scan from the hand: stop at an empty page frame or a resident one with reference bit 0; otherwise clear its reference bit and advance cyclically. Install the requested memory page with reference bit 1 and advance the hand to the next page frame. Hits leave the hand where it is. This fixes a particular variant; clean-victim preference is excluded.^[ref]

After the first three accesses, all reference bits are 1 and the hand is back at page frame 1. Access 4 clears all three reference bits, returns to page frame 1, evicts memory page 1, installs memory page 4, and leaves the hand at page frame 2 with reference bits $(1,0,0)$. This variant gives nine misses for three page frames and ten for four on the displayed sequence. Approximating LRU replacement therefore does not inherit the LRU stack property.

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