Assume the impulse point is in the interior, . Expand the displacement in the fixed-end Fourier sine series
Orthogonality gives the initial velocity coefficient by applying the Dirac delta to the sine function:
Substitution in the wave equation yields . For , its roots are , where . The two initial conditions determine
Hence the normalized velocity-impulse Green function for a damped string is
For a mode with critical damping, use the limit in place of the time factor. For , put and use . These choices solve the same modal ordinary differential equation and initial conditions, so the formula covers arbitrary . The impulse initial velocity is a distribution, so initial differentiation of the series is interpreted distributionally.
The printed formula requires correction: the factor depending on must lie inside the sum, and sine-mode normalization requires , rather than . The printed slash after the final sine is also stray. Direct differentiation at verifies the corrected normalization: the initial sine coefficients are exactly those of .
A mode has dimensionless damping ratio , and characteristic roots
If , the normal mode oscillates at with exponentially decaying envelope . As , the solution approaches the undamped wave equation response.
If , the roots are real and negative, with
The mode has a fast transient and a slow nonoscillatory relaxation. After the fast transient, neglecting gives the diffusion equation for these long-wavelength modes. At , the repeated root produces : this is critical damping.
Thus the critical parameter is for each mode, and the fundamental threshold is
When every mode is oscillatory. For any fixed, finite , sufficiently large still gives oscillatory modes, so large damping of the lowest modes does not mean that every mode of the full string is overdamped.

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